传递核心数据对象而不是一个对象

Question

常

在segues中，我完整地传递了coredata对象实例，例如

if segue.identifier == "postCall" { let vc: PostCallViewController = segue.destinationViewController as PostCallViewController let indexPath = tableView.indexPathForSelectedRow() let cell = fetchedResultsController.objectAtIndexPath(indexPath!) as Contacts vc.contact = cell }

但

这次我想加载来自不同来源的数据的vc.contact

@IBOutlet weak var pic: UIImageView!

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    if segue.identifier == "numberSelected" {
        let vc: EditViewController = segue.destinationViewController as EditViewController

        vc.contact.status = "newCall"
        vc.contact.created = NSDate()
        vc.contact.phone = selectedNumber
        vc.contact.phoneType = selectedType
        vc.contact.name = nameLabel.text!
        vc.contact.photo = UIImageJPEGRepresentation(pic.image,1)
        vc.contact.memo = ""
    }
}

editcontroller

class EditViewController: UIViewController {
    @IBOutlet weak var nameField: UITextField!
    @IBOutlet weak var phoneLabel: UILabel!
    @IBOutlet weak var numField: UITextField!

    @IBOutlet weak var userPic: UIImageView!
    @IBOutlet weak var memoArea: UITextView!

    var img:NSData!
    var contact: Contacts!
    let appDelegate = (UIApplication.sharedApplication().delegate as AppDelegate)

    let managedObjectContext = (UIApplication.sharedApplication().delegate as AppDelegate).managedObjectContext

    override func viewDidLoad() {
        super.viewDidLoad()

        nameField.text = contact?.name
        phoneLabel.text = contact?.phoneType
        numField.text = contact?.phone
        memoArea.text = contact?.memo
        img = contact?.photo
        userPic.image = UIImage(data: img)
    }

错误

我继续获得可选的nil错误 vc.contact.phone = selectedNumber 以及该块中的其余行，即使它们都不是可选变量。

问题

这种类型的传递数据是否允许将coredata对象分解为其属性？ 我想我可以在不使用核心数据的情况下单独传递变量，但是还有另一个segue导致使用coredata联系实体的同一个控制器，我希望保持一致