#include <stdio.h>
#include <stdlib.h>
float average_score(int** array_score)
{
int i, j;
int sum = 0;
for(i = 0; i < 4; i++)
{
for(j = 0; j < 4; j++)
{
sum += *(*(array_score + i) + j);
}
}
printf("sum / 16 = %d\n", sum / 16);
return (float) sum / 16;
}
int lowest_score(int** array_score)
{
int i, j;
int temp = **array_score;
for(i = 0; i < 4; i++)
{
for(j = 0; j < 4; j++)
{
if(temp > *(*(array_score + i) + j))
//------
temp = *(*(array_score + i) + j);
printf("%d ",*(*(array_score + i) + j));
}
//--
printf("\n");
}
printf("low_score = %d\n", temp);
return temp;
}
int main(int argc, char** argv)
{
int **array_score = NULL;
int i = 0;
int j = 0;
//Create a two-dimensional array
array_score = (int **) malloc(4 * sizeof(int *));
for(i = 0; i <= 4; i++)
array_score[i] = (int *)malloc(4 * sizeof(int));
//--
for(i = 0; i < 4; i++)
{
printf("Please enter the student_%d four grades, (separated with a space )\n", i+1);
int ret = scanf("%d %d %d %d", (*(array_score + i) + 0), (*(array_score + i) + 1),
(*(array_score + i) + 2), (*(array_score + i) + 3));
fflush(stdin);
if(4 != ret)
i--;
}
//There is something wrong with the function return value
float ave_score = average_score(array_score);
//--
int low_score = lowest_score(array_score);
//The output
printf("average score: %d\n lowest score: %d\n", ave_score, low_score);
return 0;
}
答案 0 :(得分:1)
这为4个指针分配空间然后写入5,因为i
采用值0,1,2,3和4:
array_score = (int **) malloc(4 * sizeof(int *));
for(i = 0; i <= 4; i++)
array_score[i] = (int *)malloc(4 * sizeof(int));
请注意,在C中,您不应该从malloc转换返回值。 Stackoverflow上有一个答案,说明为什么这没有帮助。