Question

System.out.println("Thats cool, I have thought that was a very interesting activity, how   many hours a week do you do that.");
String oftenHangOut = input.nextLine();

下一行存在问题，我不知道如何修复它。

int oftenHangOut = integer.parseInt(oftenHangOut);
if (oftenHangOut > 10){
    System.out.println("Wow thats a lot you must love to do that.");
}
else{
    System.out.println("Cool, you must love to do that.");
}

Answer 1

我无法在任何地方看到Scanner对象;）但是，我想，你想做类似的事情：

    Scanner sc = new Scanner(System.in);
    System.out.println("Thats cool, I have thought that was a very interesting activity, how   many hours a week do you do that.");
    String oftenHangOut = sc.nextLine();
    int parsedInt = Integer.parseInt(oftenHangOut);
    if (parsedInt > 10) {
        System.out.println("Wow thats a lot you must love to do that.");
    } else {
        System.out.println("Cool, you must love to do that.");
    }

或没有解析：

    Scanner sc = new Scanner(System.in);
    System.out.println("Thats cool, I have thought that was a very interesting activity, how   many hours a week do you do that.");
    int oftenHangOut = sc.nextInt();

    if (oftenHangOut > 10) {
        System.out.println("Wow thats a lot you must love to do that.");
    } else {
        System.out.println("Cool, you must love to do that.");
    }

好的技巧是使用try-catch块。你会看到出了什么问题，以及为什么你的appliaction停止了。

Answer 2

int oftenHangOut = Integer.parseInt(oftenHangOut);

并读取一个int你应该这样做

int oftenHangOut = input.nextInt();

扫描仪出错

2 个答案: