我必须模拟蚂蚁在他们家(黑盒子)和食物(黄盒子)之间移动。这些三色盒子是蚂蚁。我写的用于绘制图的代码如下:
% background
background()
% making ants
handle = zeros(10,3)
handle = makingAnts(10) ;
% moving ants
movingAnts(hand)
功能背景:
function background()
figure
hold on
axis equal
axis([0 100 0 100])
pos = rand(1,2).*75
rectangle('position',[0 0 10 10],'facecolor','k')
rectangle('position',[pos 25 25],'facecolor','y')
end
制作蚂蚁的功能:
function [h] = makingAnts(n)
h = zeros(10,3)
dia = [2 2]
for i = 1:n
pos = rand(1,2).* 95 ;
h(i,1) = rectangle('position',[pos dia],'facecolor',[0.2 0.6 1])
g1 = get(h(i,1),'position')
h(i,2) = rectangle('position',[(g1(1)+2) (g1(2)+2) 2 2],'facecolor',[0.4 1 0.6])
h(i,3) = rectangle('position',[(g1(1)+4) (g1(2)+4) 2 2],'facecolor',[1 0.8 1])
end
end
现在我必须移动蚂蚁。虽然我已经编写了代码,但它无法正常工作。我需要帮助让蚂蚁移动。
我写的代码:
function movingAnts(h)
% moving 1 ant
pos = get(h(1),'position')
m = pos(1)
n = pos(2)
for i = 1:50
set(h(1),'position',[(m+0.2) (n+0.2) 2 2])
pause(0.05)
end
end
答案 0 :(得分:4)
figure
axis([0 100 0 100])
rectangle('position',[0 0 5 5],'facecolor','k')
rectangle('position',[95 95 100 100],'facecolor','y')
n = 5;
x = zeros(1,n);
y = zeros(1,n);
c = ones(1,n);
while 1
for i = 1 : n
h1(i) = rectangle('position',[x(i) y(i) 2 2],'facecolor',[0.2 0.6 1]);
g1 = get(h1(i),'position');
h2(i) = rectangle('position',[(g1(1)+2) (g1(2)+2) 2 2],'facecolor',[0.4 1 0.6]);
h3(i) = rectangle('position',[(g1(1)+4) (g1(2)+4) 2 2],'facecolor',[1 0.8 1]);
x(i) = x(i) + c(i) * randi(4,1);
y(i) = y(i) + c(i) * randi(4,1);
if x(i) > 100 || y(i) > 100
c(i) = -1 * c(i);
x(i) = 100; y(i) = 100;
end
if y(i) < 0 || x(i) < 0
c(i) = -1 * c(i);
x(i) = 0; y(i) = 0;
end
end
pause(.1)
delete(h1,h2,h3);
end
答案 1 :(得分:4)
正如@ franz1指出的那样,问题是m
和n
变量在循环之外,因此不会更新。
为了扩展他/她的答案,这里有一个movingAnts.m
函数:
function movingAnts(h)
h = reshape(h,numel(h),[]);
for i = 1:50
pos = get(h,'position');
% move all ants
pos = cellfun(@(x) x+[1,1,0,0], pos, 'UniformOutput', false);
set(h,{'position'},pos);
drawnow update %display updates
pause(0.1);
end
end
此外,您应该将h
中makingAnts.m
的定义更改为:
h = zeros(n,3);
答案 2 :(得分:2)
for i = 1:50
set(h(1),'position',[(m+0.2) (n+0.2) 2 2])
pause(0.05)
end
由于m, n
是常量,所以在这里你将蚂蚁放在每次迭代中的相同位置。