Question

我有一些Parse代码接收推送数据并设置一个正常的通知，但问题是onPushOpen声明。我想在我的应用程序中打开一个特定的活动，但onPushOpen似乎永远不会被调用或只是不工作？

这是我的代码：

public class NotificationReceiver extends ParsePushBroadcastReceiver {
    private static final String TAG = "MYTAG";


   @Override
    public void onReceive(Context context, Intent intent) {
       Parse.setLogLevel(Parse.LOG_LEVEL_VERBOSE);
        Log.i(TAG, "Notification received");
        Bundle extras = intent.getExtras();
        String message = extras != null ? extras.getString("com.parse.Data") : "";
        JSONObject jObject;
        String alert = null;
        String title = null;
        try {
            jObject = new JSONObject(message);
            alert = (jObject.getString("alert"));
            title = (jObject.getString("title"));
        }
        catch (JSONException e) {
            e.printStackTrace();
        }

        Log.i(TAG,"alert is " + alert);
        Log.i(TAG,"title is " + title);
        NotificationCompat.Builder notification =
                new NotificationCompat.Builder(context)
                        .setSmallIcon(R.drawable.ic_launcher)
                        .setContentTitle(alert)
                        .setContentText(title);


        NotificationManager mNotificationManager = (NotificationManager) context.getSystemService(Context.NOTIFICATION_SERVICE);
        mNotificationManager.notify(1, notification.build());
        Log.i(TAG, "Notification created");

   }


    @Override
    protected void onPushOpen(Context context, Intent intent) {
        Log.i(TAG, "Notification clicked");
        Intent i = new Intent(context, MainActivity.class);
        i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        context.startActivity(i);
    }
}

我似乎无法弄清楚为什么onPushOpen不会启动我请求的活动（MainActivity）。任何帮助将不胜感激。

Answer 1

我面临着与onPushOpen()方法相同的问题，但如果您只是想打开自己的活动，那么可以解决一些问题。您可以使用Pending Intent这样解决问题：

NotificationCompat.Builder notification =
            new NotificationCompat.Builder(context)
                    .setSmallIcon(R.drawable.ic_launcher)
                    .setContentTitle(alert)
                    .setContentText(title);

// create intent to start your activity
Intent activityIntent = new Intent(context, MainActivity.class);

// create pending intent and add activity intent
PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, activityIntent,
    PendingIntent.FLAG_UPDATE_CURRENT);
notification.setContentIntent(pendingIntent);

// Add as notification
NotificationManager mNotificationManager = (NotificationManager) context.getSystemService(Context.NOTIFICATION_SERVICE);
    mNotificationManager.notify(1, notification.build());

所以没有必要调用onPushOpen()方法，因为一旦点击通知，待处理的意图就会开始你的活动。

显示解析通知，打开操作不启动活动

1 个答案: