Question

出于某种原因，我的计算结果不正确。我试图做的就是找到用户输入的3个数字的平均值。如果需要更多，请点击这里的def，只要问一下。

#===================== Calculates the average of all three ==========================

def calc_average(self): #average calculation
    stop_one_mileage = self.__route[0].stop_one_mileage #stop_one_mileage average
    stop_two_mileage = self.__route[0].stop_two_mileage #stop_two_mileage
    stop_three_mileage = self.__route[0].stop_three_mileage #stop_three_mileage
    avg = int(stop_one_mileage) + int(stop_two_mileage) + int(stop_three_mileage)/3 #adds all three and divides by three
    return "<div class='results-container'><span class='title'>Average Mileage: </span><span class='results-container'>" + str(avg) + " miles</span></div>" #returns results

Answer 1

也许您忘了使用括号？

avg = (int(stop_one_mileage) + int(stop_two_mileage) + int(stop_three_mileage))/3

否则它只将最后一个数字除以3然后将其他数字相加。看看Python operator precedence documentation。

Answer 2

问题在于：

avg = int(stop_one_mileage) + int(stop_two_mileage) + int(stop_three_mileage)/3

将其更改为：

avg = (int(stop_one_mileage) + int(stop_two_mileage) + int(stop_three_mileage))/3

因为这就是发生的事情：

>>> 2 + 2 + 2 / 3
4
>>> (2 + 2 + 2) / 3
2

Python平均3个数字计算

2 个答案: