Question

以下代码将结果延迟2秒。我想要的是立即返回结果，但每2秒启动一个新的observable。我缺少什么？

输出：

**The current output is:**
05: 1. Run
07 Result: 1

07: 2. Run
09 Result: 2

09: 3. Run
11 Result: 3


**Desired output is:**
05: 1. Run
05 Result: 1

07: 2. Run
07 Result: 2

09: 3. Run
09 Result: 3

CODE：

    var sources = Enumerable.Range(1, 8).Select(i =>
                                                {
                                                    Console.WriteLine("{0}: {1}. Run", DateTimeOffset.Now.ToString("ss"), i);

                                                    return Observable.Return(i, CurrentThreadScheduler.Instance);
                                                });

    Observable.Generate(sources.GetEnumerator(), e => e.MoveNext(), e => e, e => e.Current, e => TimeSpan.FromMilliseconds(2000), ThreadPoolScheduler.Instance)
              .Merge()
              .Timestamp()
              .Do(r =>
                  {
                      Console.WriteLine("{0} Result: {1}{2}", r.Timestamp.ToString("ss"), r.Value, Environment.NewLine);
                  },
                  ex =>
                  {
                      Console.WriteLine(ex.ToString());
                  },
                  () =>
                  {
                      Console.WriteLine("Completed");
                  })
              .Subscribe();

Answer 1

怎么样：

Observable.Interval(TimeSpan.Zero, TimeSpan.FromSeconds(2.0))
    .SelectMany(_ => GenerateAnObservable())
    .Subscribe(/* ... */);

Answer 2

如何用这个替换当前的Observable.Generate：

Observable
    .Generate(
        0,
        i => true,
        i => i + 1,
        i => i,
        i => TimeSpan.FromMilliseconds(i == 0 ? 0 : 2000),
        ThreadPoolScheduler.Instance)
    .Zip(sources, (g, s) => s)

我得到了这个结果：

41: 1. Run
41 Result: 1

43: 2. Run
43 Result: 2

45: 3. Run
45 Result: 3

47: 4. Run
47 Result: 4

49: 5. Run
49 Result: 5

51: 6. Run
51 Result: 6

53: 7. Run
53 Result: 7

55: 8. Run
55 Result: 8

Completed

Observable.Generate延迟结果

2 个答案: