循环数组没有给出所需的结果

Question

我正在编写一个从一个表（release_dates）获取信息的脚本，但也从不同的表中获取X个屏幕截图列表（release_screenshots）。然后它将所有信息放入一个数组中，并将其编码为JSON。

但是，每个JSON条目都有完全相同的屏幕截图列表。

以下是我的代码片段：

$json_response = array();

while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $row_array['id'] = $row['id'];
    $row_array['game_title'] = $row['game_title'];
    $row_array['game_platform'] = $row['game_platform'];
    $row_array['game_genre'] = $row['game_genre'];
    $row_array['game_publisher'] = $row['game_publisher'];
    $row_array['release_eu'] = $row['release_eu'];
    $row_array['release_us'] = $row['release_us'];
    $row_array['rrp_gbp'] = $row['rrp_gbp'];
    $row_array['rrp_eur'] = $row['rrp_eur'];
    $row_array['rrp_usd'] = $row['rrp_usd'];
    $row_array['link_address'] = $row['link_address'];
    $row_array['logo_image'] = $row['logo_image'];
    $row_array['box_art'] = $row['box_art'];

    //Build incrementing variable name
    $ssno = 1;
    $ss = "ss_".$ssno;

    //Get the list of screenshots where the referring ID is = to the current ID
    $query2 = "SELECT * FROM release_screenshots WHERE parent_id = '$row_array[id]'";
    $result2 = mysql_query($query2);
    while($row2 = mysql_fetch_array($result2)){
        $array[] = $row2;
    }

    //Add each Screenshot link to the array build and increment the variable name
    foreach($array as $x){

        $row_array[$ss] = $x['link'];
        $ssno = $ssno + 1;
        $ss = "ss_".$ssno;
    }

    $row_array['youtube_link'] = $row['youtube_link'];
    $row_array['notes'] = $row['notes'];
    $row_array['entry_created'] = $row['entry_created'];


    array_push($json_response,$row_array);
}
echo json_encode($json_response);

我希望我已经解释得这么好了。如果没有，我可以提供进一步的信息。 任何帮助将不胜感激。

Answer 1

您需要在第二个$array循环之前清除while。否则，您将添加上一个游戏中的数组。

$query2 = "SELECT * FROM release_screenshots WHERE parent_id = '$row_array[id]'";
$result2 = mysql_query($query2);
$array = array();
while($row2 = mysql_fetch_array($result2)){
    $array[] = $row2;
}

您还需要在外部$row_array循环的开头清除while：

while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $row_array = array();
    ...