在C ++中,我试图输入电影的名称和数年的发布并将它们存储在数据库/结构中。在我要求输入标题和年份之前。我让用户使用凭据登录。在这种情况下,用户名是"锈蚀"密码是"锈蚀"。
我遇到的问题是在验证凭据之后,跳过输入数据库/结构的第一个电影标题。我相信这与我使用_getch
功能有关,但我并不完全确定。
我的代码如下。我的输出如下:
Please enter your username
rusty
Please enter your password
Access granted! Welcome rusty
Enter title: Enter year: (input movie year)
Enter title: (input movie title)
Enter year: (input movie year)
Enter title: (input movie title)
....
#include <iostream>
#include <string>
#include <sstream>
#include <conio.h>
using namespace std;
//function prototype
int username_and_pass();
#define NUM_MOVIES 6
struct movies_list{
string title;
int year;
}films[NUM_MOVIES];
// prototype with function declaration
void sort_on_title(movies_list films[], int n)
{
movies_list temp;
for (int i = 0; i < n - 1; i++)
{
if (films[i].title>films[i + 1].title)
{
temp = films[i];
films[i] = films[i + 1];
films[i + 1] = temp;
}
}
}// end of sort_on_title function
void printmovie(movies_list movie)
{
cout << movie.title;
cout << " (" << movie.year << ") \n";
}
void search_on_title(movies_list films[], int n, string title)
{
bool flag = false;
for (n = 0; n < NUM_MOVIES; n++)
{
if (films[n].title == title)
{
cout << "Title: " << films[n].title << endl;
cout << "Year of Release: " << films[n].year << endl;
cout << "\n";
flag = true;
}
}
if (flag == false)
cout << "Search on title not found!" << endl;
}// end of search_on_title function
void search_on_year(movies_list films[], int n, int year)
{
bool flag = false; // check on existence of record
for (n = 0; n < NUM_MOVIES; n++)
{
if (films[n].year == year) // display if true
{
cout << "Title: " << films[n].title << endl;
cout << "Year of Release: " << films[n].year << endl;
cout << "\n";
flag = true;
}
}
if (flag = false)
cout << "Search on title not found!" << endl;
}// end of search_on_title function
int menu()
{
int choice;
cout << " " << endl;
cout << "Enter 1 to search on titles " << endl;
cout << "Enter 2 to search on years " << endl;
cin >> choice;
cout << "\n";
return choice;
}// end of menu function
int username_and_pass()
{
string uName;
string password;
int value;
char ch;
cout << "Please enter your username\n";//"rusty"
cin >> uName;
cout << "Please enter your password\n";//"rusty"
ch = _getch();
while (ch != 13)//As long as the user doesn't press Enter
{//(enter is ASCII code 13) continue reading keystrokes from the screen.
password.push_back(ch);
cout << '*';
ch = _getch();
}
if (uName == "rusty" && password == "rusty")
{
cout << "\n\nAccess granted! Welcome " << uName << "\n\n" << endl;
value = 1
}
else
{
cout << "Invalid credentials" << endl;
value = 0;
}
return value;
}// end of username_and_pass function
int main()
{
string mystr;
int n;
string response;
int value = 0;
do
{
value = username_and_pass();
} while (value==0);
if(value==1)
{
for (n = 0; n < NUM_MOVIES; n++)
{
cout << "Enter title: ";
getline(cin, films[n].title);
cout << "Enter year: ";
getline(cin, mystr);
stringstream(mystr) >> films[n].year;
}
//sorts records
sort_on_title(films, NUM_MOVIES);
cout << "\nYou have entered these movies:\n";
for (n = 0; n < NUM_MOVIES; n++)
printmovie(films[n]);
//menu
int choice = 0;
choice = menu();
if (choice == 1)
{
string searchTerm;
cout << "What is the movie you want to search for? " << endl;
cin >> searchTerm;
cout << " " << endl;
search_on_title(films, NUM_MOVIES, searchTerm);
}
else
{
int searchTermYear;
cout << "What is the year you want to search for? " << endl;
cin >> searchTermYear;
cout << " " << endl;
search_on_year(films, NUM_MOVIES, searchTermYear);
}
cout << "Would you like to query the database again? (Y/N)" << endl;
cin >> response;
if (response == "Y" || "y")
{
choice = menu();
if (choice == 1)
{
string searchTerm;
cout << "What is the movie you want to search for? " << endl;
cin >> searchTerm;
cout << " " << endl;
search_on_title(films, NUM_MOVIES, searchTerm);
}
else
{
int searchTermYear;
cout << "What is the year you want to search for? " << endl;
cin >> searchTermYear;
cout << " " << endl;
search_on_year(films, NUM_MOVIES, searchTermYear);
}
}
}
return 0;
}
答案 0 :(得分:1)
答案 1 :(得分:0)
我不确定是什么原因导致了这个问题。但是你可以尝试使用cin.clear()。在你要求输入标题之前放置它。
cin.clear();
cout << "Enter title: ";
getline(cin, films[n].title);
cout << "Enter year: ";
getline(cin, mystr);
stringstream(mystr) >> films[n].year;