Question

我绞尽脑汁想出这个......我知道它的一些简单但我需要一套新的眼睛来弄清楚我错过了什么？

行包含**，从底部开始第7行

我收到错误C2660：＆＃39; drillOneProblem＆＃39; ：function不带3个参数。请帮忙！

// Drill into problem
void drillOneProblem()
{
int c, r1, r2; // passed-in parameters
int CorAns; // correct answer
int reply; // user's answer

// Ask first part of question and display first random number
cout << "\nWhat is " << r1;

// Display sign based on user's answer
switch (c)
{
    case '1': cout << " + ";
    CorAns = r1 + r2;
    break;
    case '2': cout << " - ";
    CorAns = r1 - r2;
    break;
    case '3': cout << " * ";
    CorAns = r1 * r2;
    break;
}

// Finish question and display second random number
// Ask answer, validate answer and display message
cout << r2 << " ? ";
cin >> reply;

if (reply == CorAns)
{
cout << "Yes, that is corret. Good job!";
}
else
cout << "No, the correct answer is: " << CorAns << endl << endl;
}

int main()
{
    int c; // user's menu choice
    int r1, r2; // random numbers

    //Display Menu
    displayMenu();

   // Get user's choice and validate if out of range
   c = getMenuChoice();

   // Continue with program if user doesn't quit
   while (c >= 1 && c < SENT)
{
    // Generate random numbers
    Gen2Rand(r1, r2);

    // Display question based on user's menu choice request answer and validate answer. 
    // Display message to show if correct or not correct. If not correct display correct answer
    **drillOneProblem(c, r1, r2);**

    // display menu again and ask for menu choice after problem has been processed, repeat until  
    user quits
    displayMenu();
    c = getMenuChoice();
    } return 0;
}

Answer 1

参数需要在函数声明的括号中声明。

所以这个：

void drillOneProblem()
{
int c, r1, r2; // passed-in parameters

应该是这样的：

void drillOneProblem(int c, int r1, int r2)
{

Answer 2

将您的职能声明为

void drillOneProblem(int c, int r1, ,int r2)

并在函数

中删除具有相同名称的局部变量

Answer 3

您的功能声明（第一行）中没有参数

void drillOneProblem()

它应该是：

void drillOneProblem(int c, int r1, int r2){

Answer 4

你的宣言中没有参数

 void drillOneProblem()

它应该是 void drillOneProblem（int c，r1，r2）;

你应该删除你的fuc中的varriables，如：

void drillOneProblem(int c, r1, r2)
  {
  //int c, r1, r2; // passed-in parameters
  .....
  }

C ++错误C2660：函数不带3个参数

4 个答案: