我正在使用NHibernate,并试图找出如何编写查询,搜索我的实体的所有名称, 并列出结果。举个简单的例子,我有以下几个对象;
public class Cat {
public string name {get; set;}
}
public class Dog {
public string name {get; set;}
}
public class Owner {
public string firstname {get; set;}
public string lastname {get; set;}
}
Eventaully我想创建一个查询,比如说,并且返回所有宠物主人,其名称包含“ted”,OR宠物的名称包含“ted”。
以下是我想要执行的SQL的示例:
SELECT TOP 10 d.*, c.*, o.* FROM owners AS o
INNER JOIN dogs AS d ON o.id = d.ownerId
INNER JOIN cats AS c ON o.id = c.ownerId
WHERE o.lastname like '%ted%'
OR o.firstname like '%ted%'
OR c.name like '%ted%'
OR d.name like '%ted%'
当我使用Criteria这样做时:
var criteria = session.CreateCriteria<Owner>()
.Add(
Restrictions.Disjunction()
.Add(Restrictions.Like("FirstName", keyword, MatchMode.Anywhere))
.Add(Restrictions.Like("LastName", keyword, MatchMode.Anywhere))
)
.CreateCriteria("Dog").Add(Restrictions.Like("Name", keyword, MatchMode.Anywhere))
.CreateCriteria("Cat").Add(Restrictions.Like("Name", keyword, MatchMode.Anywhere));
return criteria.List<Owner>();
生成以下查询:
SELECT TOP 10 d.*, c.*, o.* FROM owners AS o
INNER JOIN dogs AS d ON o.id = d.ownerId
INNER JOIN cats AS c ON o.id = c.ownerId
WHERE o.lastname like '%ted%'
OR o.firstname like '%ted%'
AND d.name like '%ted%'
AND c.name like '%ted%'
如何调整查询以使.CreateCriteria(“Dog”)和.CreateCriteria(“Cat”)生成OR而不是AND?
感谢您的帮助。
答案 0 :(得分:5)
试试这个,它可能有用。
var criteria = session.CreateCriteria<Owner>()
.CreateAlias("Dog", "d")
.CreateAlias("Cat", "c")
.Add(
Restrictions.Disjunction()
.Add(Restrictions.Like("FirstName", keyword, MatchMode.Anywhere))
.Add(Restrictions.Like("LastName", keyword, MatchMode.Anywhere))
.Add(Restrictions.Like("c.Name", keyword, MatchMode.Anywhere))
.Add(Restrictions.Like("d.Name", keyword, MatchMode.Anywhere))
);
答案 1 :(得分:2)
您需要使用Expression.Or(criteria1,criteria2)
组合这两个条件嗯,我觉得它看起来像这样(借用了BuggyDigger的代码)
var criteria = session.CreateCriteria<Owner>()
.CreateAlias("Dog", "d")
.CreateAlias("Cat", "c")
.Add(Expression.Or(Expression.Like("c.Name", keyword, MatchMode.Anywhere)
, Expression.Like("d.Name", keyword, MatchMode.Anywhere))
);
但是我没注意到你想要一切东西。在这种情况下,正如BuggyDigger所示,将这些标准添加到析取中可能是要走的路。