Question

输入要处理的文件后，命令行跳转到下一行但保持空白，而不是打印所需的数组。我想调用getInputScanner（）方法来生成访问该文件的扫描程序，在用户输入文件后，命令行跳转到下一行，而不是处理任何文本。有什么想法吗？

 import java.util.*;
 import java.awt.*;
 import java.io.*;


public class Test {
   public static void main(String [] args) { 

      Scanner console = new Scanner(System.in);

      Scanner input = getInputScanner(console);

      System.out.println("{" + nameArr(input) + "}");

   }

   public static Scanner getInputScanner(Scanner console) {

      System.out.print("Please enter a file to process: ");
      File file = new File(console.next());
      while (!file.exists()) {
         System.out.print("\nFile does not exists.\nPlease enter a new file name: ");
         file = new File(console.next());
      }
      try {
         Scanner fileScanner = new Scanner(file);
         return fileScanner;
      } catch (FileNotFoundException e) {
         System.out.println("File not found");
        }
      return null;
    }

   public static String [] nameArr(Scanner input) {

      int count = 0;
      while (input.hasNextLine()) {
         count++;
      }

      String [] nameArray = new String[count];

      while (input.hasNextLine()) {

         String line = input.nextLine();

         for (int i = 0; i < nameArray.length; i++) {
            nameArray[i] = lineProcess(input.nextLine());
         }
      }
      return nameArray;
   }

   public static String lineProcess(String line) {
      Scanner lineScan = new Scanner(line);

      String line2 = lineScan.nextLine();

      String lineString[] = line2.split(" ");

      String name = lineString[0];

      return name;

   }


}

Answer 1

您已经无限loop因为您没有推进扫描程序调用{{1}}：

input.nextLine()

我看到代码的其他部分我错了，尝试使用while (input.hasNextLine()) { count++; }代替java.util.List来收集处理文件行中的array ：

names

命令行返回空白

1 个答案: