Question

我有以下形式的MongoDB数据：

{"_id":"53eb9a5673a57578a10074ec","data":{"statistics":{"gsm":[{"type":"Attacks","value":{"team1":66,"team2":67}},{"type":"Corners","value":{"team1":8,"team2":5}},{"type":"Dangerous attacks","value":{"team1":46,"team2":49}},{"type":"Fouls","value":{"team1":9,"team2":14}},{"type":"Free kicks","value":{"team1":18,"team2":10}},{"type":"Goals","value":{"team1":2,"team2":1}},{"type":"Goal kicks","value":{"team1":10,"team2":11}},{"type":"Offsides","value":{"team1":1,"team2":4}},{"type":"Posession","value":{"team1":55,"team2":45}},{"type":"Shots blocked","value":{"team1":4,"team2":1}},{"type":"Shots off target","value":{"team1":7,"team2":5}}]}}}

我想得到data.statistics.gsm.type ==＆＃34; Attacks＆＃34;使用Golang MongoDB驱动程序mgo。到目前为止我已尝试过的代码（使用下面的一个或两个组语句）：

pipeline := []bson.M{
    bson.M{"$match": bson.M{"kick_off.utc.gsm.date_time": bson.M{"$gt": start, "$lt": end}}}, 
bson.M{
        "$group": bson.M{
            "_id":     "$gsm_id",
    "event_array" : bson.M{"$first": "$data.statistics.gsm"}}},
bson.M{
            "$group": bson.M{
                "_id":     "$type",
          "avg_attack" : bson.M{"$avg": "$data.statistics.gsm.value.team1"}}}}

只有第一组声明，我回到下面，但第二组声明并没有帮助我获得平均值。

[{"_id":1953009,"event_array":[{"type":"Attacks","value":{"team1":48,"team2":12}},{"type":"Corners","value":{"team1":12,"team2":0}},{"type":"Dangerous attacks","value":{"team1":46,"team2":7}},{"type":"Fouls","value":{"team1":10,"team2":3}},{"type":"Free kicks","value":{"team1":5,"team2":12}},{"type":"Goals","value":{"team1":8,"team2":0}}

Answer 1

我总是觉得获得json的漂亮打印视图很有帮助。以下是您从第一组声明中得到的结论：

[  
{  
"_id":1953009,
"event_array":[  
  {  
    "type":"Attacks",
    "value":{  
      "team1":48,
      "team2":12
    }
  },
  {  
    "type":"Corners",
    "value":{  
      "team1":12,
      "team2":0
    }
  },
...

现在使用的第二个群组声明：

"$group": bson.M{
     "_id":     "$type",
     "avg_attack" : bson.M{"$avg": "$data.statistics.gsm.value.team1"}
}

你试图在第一组声明的结果中取data.statistics.gsm.value.team1的平均值，但在第一组声明的结果中不存在，所以当然它不会给你一个平均。

而不是你正在使用的方法，我建议调查$unwind operator将数组分解为一组文档，然后你应该能够按照你想要的方式对它们进行分组这里有{$avg: "$value.team1"}。

因此，用于生成聚合的整个管道将是：$match -> $group1 -> $unwind -> $group2。请记住，管道的每个阶段都在对前一阶段生成的数据进行操作，这就是data.statistics.gsm.value.team1部分不正确的原因。

具有嵌套数组的Golang MongoDB（mgo）聚合

1 个答案: