我正在尝试解析来自db(2014-06-11 16:58:12.903)的日期,如下所示
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", new Locale("tr-TR"));
String tarih = cursor.getString(cursor.getColumnIndex("Created");
tarih = tarih.replace("T", " ");
Object.Created = dateFormat.parse(tarih);
下面的代码返回" Fri Dec 04 16:58:12 EET 16"
DateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss", new Locale("tr-TR"));
String tarih = cursor.getString(cursor.getColumnIndex(field.getName()));
Object.Created = dateFormat.parse(tarih);
此方法返回的日期类似于" Wed Jun 11 16:58:12 EEST 2014"
我如何获得像dd-MM-YYYY> 11-06-2014
这样的日期答案 0 :(得分:0)
//在方法中添加以下代码行。
SimpleDateFormat fmtOut = new SimpleDateFormat("dd-MM-yyyy");
return fmtOut.format(tarih);
请注意这个因素约一个月。 (要获得今天的约会)
final Calendar c = Calendar.getInstance();
int year = c.get(Calendar.YEAR);
int month = c.get(Calendar.MONTH)+1; // INCREMENT MONTH VALUE BY 1 (we get 0 for january and 11 for december)
month_name = map_instance.findMonthName(month+"");
int day = c.get(Calendar.DAY_OF_MONTH);
//年份值的问题可能是因为从数据库中恢复的数据
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", new Locale("tr-TR"));
String tarih ="";
try
{
tarih = dateFormat.parse(cursor.getString(cursor.getColumnIndex("Created"));
}catch (ParseException e) {
tarih = "";
}
log.w("Data from database",tarih);
tarih = tarih.replace("T", " ");
Object.Created = tarih;