sql查询找出连续出现的相同字符

Question

需要有一个Oracle SQL查询，该查询将找出特定字段值连续字符出现次数超过2次的行

Field1
---------------
asdfgh
asdewr
aaasdf
sssrty
sswasv
vvvruy8
<<this keeps going>>

从上面

，只需要在下面选择：

aaasdf
sssrty
vvvruy8

Answer 1

尝试使用regexp_like，如下所示：

select  field from 
(select 'asdaaa' field from dual 
 union all select 'asdxx' from dual 
 union all select 'asdxxx' from dual 
 union all select 'asd1111' from dual) 
WHERE REGEXP_LIKE(field, '(.+?)\1{2,}?')

返回具有3个或更多次出现的连续字符的字符串：

FIELD  
-------
asdaaa 
asdxxx 
asd1111

3 rows selected.

Answer 2

按这样的字母查询：

SELECT fieldname
FROM tablename
WHERE SUBSTR(fieldname, 1, 1) = SUBSTR(fieldname, 2, 1)
AND   SUBSTR(fieldname, 1, 1) = SUBSTR(fieldname, 3, 1);