Dojo Lazy Tree Grid - 按需网格更改数据

Question

我有Dojo Lazy Tree Grid。我试图通过Ajax更改网格上的数据，而不是提交页面。

dojo.require("dojox.grid.LazyTreeGrid");
        dojo.require("dojox.grid.LazyTreeGridStoreModel");
        dojo.require("dojo.data.ItemFileWriteStore");
        dojo.require("dojox.data.QueryReadStore");
        dojo.require("dojo.parser");
        dojo.require("dijit.form.DateTextBox");
        dojo.require("dojox.grid.cells.dijit");

    var store = "";
    var qty1 = "";

    var grid ;
    dojo.ready(function(){
        qty1 = document.getElementById("qty1").value;

    if(qty1!="")
        store = new dojox.data.QueryReadStore({url: "serverdata.jsp?firsttimeload=false" });
    else
        store = new dojox.data.QueryReadStore({url: "serverdata.jsp?firsttimeload=true" });


    var model = new dojox.grid.LazyTreeGridStoreModel({
          store: store,
          serverStore: true,
          childrenAttrs: ['children']
        });

    var layout = [


        {name: 'Qty1', field: 'Qty1', width: '20%'},
        {name: 'Qty2', field: 'Qty2', width: '10%',formatter: openHyperlink}
    ];
    grid = new dojox.grid.LazyTreeGrid({
        id: 'grid',
        treeModel: model,
        structure: layout,
        openOnClick:true,
        rowSelector: '20px',
        canSort:false,
        rowsPerPage:'500'

  }, document.createElement('div'));


/* append the new grid to the div */
dojo.byId("gridDiv").appendChild(grid.domNode);

/* Call startup() to render the grid */
grid.startup();

    function search()
    {
        qty1 = document.getElementById("qty1").value;
        if(qty1!="" )
        {
            grid._clearData();
            grid._size = 500;
            grid.rowsPerPage = 500; 
            grid.updateRowCount(500);
            grid._updateRenderedRows(); 
            var jsonurl = "serverdata.jsp?firsttimeload=false&qty1="+qty1;
            grid.setStore(new dojox.data.QueryReadStore({url: jsonurl}));
            grid._fetch(0, true);
            grid.refresh();

        }
        else
        {
            alert("Please enter atleast one search term");
        }
    }

    var openHyperlink = function(value, idx, level){

        return '<a href="#">'+value+'</a>';

        } 

当我点击搜索时，我调用搜索（），我想要刷新网格。 但是当我将rowsPerPage保持为500时。浏览器本身停止响应几分钟。我得到一个脚本没有响应。我的方式是以正确的方式刷新网格的内容吗？ 请协助。