Question

我正在尝试创建一个链接列表，用于存储来自用户输入的单词，然后打印它们。我的代码有效，但是我想修改它以在每个单词后提示用户，直到最后一个单词是＆＃34;结束＆＃34;。有关如何做到这一点的任何提示？现在，代码提示用户，用户可以输入以空格分隔的单词，直到按Enter键，然后打印链表

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>

typedef struct list *ptr;
typedef struct list {
    char data;
    ptr next;
} node;

void insert(ptr *H, char c);
void freeList(ptr *H);
void printList(ptr H);

int main() {
    ptr H = NULL;
    int c;

    printf("enter a single word:\n");

    while (((c = getchar()) != EOF) && c != '\n')
        insert(&H, (char) c);

    printList(H); /*print the list*/
    freeList(&H); /*free the list*/
    printf("\n");
    prinf("Please enter a single word:\n");

    return 0;
}

void insert(ptr *H, char c) {
    while (*H)
        H = &(*H)->next;

    *H = malloc(sizeof(**H));
    (*H)->data = c;
    (*H)->next = NULL;
}

void freeList(ptr *H) {

    while (*H) {
        ptr tmp = *H;
        *H = (*H)->next;
        free(tmp);
    }
}

void printList(ptr H) {
    // NOTE: No need for a pointer-to-pointer here.
    while (H) {
        printf("%c", H->data);
        H = H->next;
    }
}

Answer 1

修改后的样本

int isEndKeyword(ptr H){
    const char *end_keyword = "end";

    while(*end_keyword){
        if(H){
            if(*end_keyword++ != H->data)
                return 0;//false
        } else //short
            return 0;
        H = H->next;
    }
    return H == NULL;//match
}

int main() {
    ptr H = NULL;
    int c;
    char prev = ' ';

    while(1){
        c = getchar();
        if(isspace(c) || c == EOF){
            if(!isspace(prev)){ //word is exist
                if(!isEndKeyword(H)){
                    printList(H); /* print the word */
                    printf("\n");
                } else {
                    c = EOF;
                }
                freeList(&H); /* free the word */
            }
            if(c == EOF)
                break;//loop end
        } else {
            insert(&H, (char) c);
        }
        prev = c;
    }

    return 0;
}

使用用户输入的单词创建和打印链接列表

1 个答案: