Question

例如我正在做这样的事情：

PlatformInformer.where(1)

并通过

查询结果

PlatformInformer.where(1).to_sql

是

SELECT `platform_informers`.* FROM `platform_informers`  WHERE `platform_informers`.`platform` = 'android' AND `platform_informers`.`email` = 'voldemar@klops.ru' AND (1)

我没有要求在where子句中添加电子邮件和平台字段！

当我在PlatforInformer模型方法中执行代码时，会出现此问题。默认范围未设置。邪恶的根源是什么？

Rails 3.2.13

更新：

class PlatformInformer < ActiveRecord::Base
  include HasUniqueGenerator

  attr_accessible :email, :platform,:secret_code,:activated,:invitation_sent

  before_create :init_secret_code

  PLATFORMS = %w(windows macos android ios)

  def self.PLATFORMS
    PLATFORMS
  end

  validates :platform, :presence => true,:inclusion => { :in =>PLATFORMS }
  validates :email, :presence => true, :email => true

  validates_uniqueness_of :email, scope: :platform

  scope :confirmed, Proc.new { where(:activated => true) }

  def several_platforms?
    PlatformInformer.confirmed.find_all_by_email(self.email).count > 0
  end

  def send_confirmation
    if already_subscribed?
      activate!
    else
      PlatformInformerMailer.inform_me(self.id).deliver
    end
  end

  def activate!
    PlatformInformer.where(:email=>self.email).update_all(:activated=>true)
  end


  private
  def init_secret_code
    gen_unique_code :secret_code, 16
  end

  def already_subscribed?
    PlatformInformer.confirmed.where(email: self.email).any?
  end

end

Answer 1

问题在于使用first_or_create方法，该方法使用电子邮件和平台属性创建了虚拟范围。

Activerecord在查询中添加了其他条件

1 个答案: