Question

我制作了一个小应用程序，我必须根据关键字检索URL。这是代码：

  Elements doc = Jsoup
        .connect(request)
        .userAgent(
          "Mozilla 5.0 (Windows NT 6.1)")
        .timeout(5000).get().select("li.g>h3>a");


        for (Element link : doc) {

              String url = link.absUrl("href"); 
            try {
              url = URLDecoder.decode(url.substring(url.indexOf('=') + 1, url.indexOf('&')), "UTF-8");
            } catch (UnsupportedEncodingException e) {
                    // TODO Auto-generated catch block
              e.printStackTrace();
            }



            if(!url.startsWith("http")) 
                continue; // Ads/news/etc.
            else if(url.contains("/pdf/"))
                continue;
            else if(url.contains("//github.com/"))
                continue;


            res.add(url);
        }

只是出现以下错误：

org.jsoup.HttpStatusException: HTTP error fetching URL. Status=503, URL=http://ipv4.google.com/sorry/IndexRedirect?continue=http://www.google.com/search%3Flr%3Dlang_en....
at org.jsoup.helper.HttpConnection$Response.execute(HttpConnection.java:435)
at org.jsoup.helper.HttpConnection$Response.execute(HttpConnection.java:446)
at org.jsoup.helper.HttpConnection$Response.execute(HttpConnection.java:410)
at org.jsoup.helper.HttpConnection.execute(HttpConnection.java:164)
at org.jsoup.helper.HttpConnection.get(HttpConnection.java:153)
at sperimentazioni.Main.getDataFromGoogle(Main.java:327)
at sperimentazioni.Main.getURLs(Main.java:164)
at sperimentazioni.Main.main(Main.java:485)

显然这是验证码谷歌，我该如何绕过？

Answer 1

以下逻辑对我有用：

Document doc =
    Jsoup.connect(request)
         .userAgent("Mozilla/5.0 (compatible; Googlebot/2.1; +http://www.google.com/bot.html)")
         .timeout(5000).get();

Elements links = doc.select("a[href]");
for (Element link : links) {

    String temp = link.attr("href");
    if (temp.startsWith("/url?q=")) 
        result.add(temp);

}

Answer 2

您无法绕过它，但您可以使用第三方服务进行CPATCHA识别并发布正确答案。查看DeatchByCaptcha.com

Answer 3

解决此问题的唯一方法是向用户显示验证码，然后从响应标题中保存cookie。

Jsoup connect（）：绕过谷歌验证码

3 个答案: