Question

我知道如何执行'高级所在'。我没有在文档中找到任何解释我想要的东西..即使在那里。（cf：http://laravel.com/docs/4.2/queries#advanced-wheres）。

Post::whereHas('international_post_en', function($q) {
       $q->where('is_published', 1);
  })->whereHas('categories', function($q) {
       $q->where('name', 'test-one');
  })->orWhereHas('subcategories', function($q) {
       $q->where('name', 'test-two');
  })->with('categories', 'subtags')
    ->get();

我的查询如下：

select * from `posts` where `posts`.`deleted_at` is null and (select count(*) from `international_posts_en` where `international_posts_en`.`posts_id` = `posts`.`id` and `is_published` = ?) >= 1 and (select count(*) from `categories` inner join `posts_has_categories` on `categories`.`id` = `posts_has_categories`.`categories_id` where `posts_has_categories`.`posts_id` = `posts`.`id` and `name` = ?) >= 1 or (select count(*) from `subcategories` inner join `posts_has_subcategories` on `subcategories`.`id` = `posts_has_subcategories`.`subcategories_id` where `posts_has_subcategories`.`posts_id` = `posts`.`id` and `name_en` = ?) >= 1

但我希望我的查询看起来像这样：

select * from `posts` where `posts`.`deleted_at` is null and (select count(*) from `international_posts_en` where `international_posts_en`.`posts_id` = `posts`.`id` and `is_published` = ?) >= 1 and [(](select count(*) from `categories` inner join `posts_has_categories` on `categories`.`id` = `posts_has_categories`.`categories_id` where `posts_has_categories`.`posts_id` = `posts`.`id` and `name` = ?) >= 1 or (select count(*) from `subcategories` inner join `posts_has_subcategories` on `subcategories`.`id` = `posts_has_subcategories`.`subcategories_id` where `posts_has_subcategories`.`posts_id` = `posts`.`id` and `name_en` = ?) >= 1[)]

（抱歉它不太可读）

您可以在括号内看到更改。所以，我希望将whereHas和orWhereHas子句分组在括号内。

是否可以使用Laravel Query Builder，还是应该进行手工查询？

提前谢谢。

Answer 1

Post::whereHas('international_post_en', function($q) {
       $q->where('is_published', 1);
  })->where(function ($q) {
     $q->whereHas('categories', function($q) {
       $q->where('name', 'test-one');
     })->orWhereHas('subcategories', function($q) {
       $q->where('name', 'test-two');
     });
  })->with('categories', 'subtags')->get();

实际上，这是您linked页面上的第一个示例。然而，这个例子非常不准确，因为你不会将and与or组合在一起，而是反过来..

执行高级where子句Eloquent

1 个答案: