Question

我正在尝试搜索我的解析成分的数组列是否包含用户给定的成分，由于某种原因，没有查询对我有用，它总是返回null。

有什么建议吗？

感谢。

enter image description here

我的代码：

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

import com.parse.FindCallback;
import com.parse.GetCallback;
import com.parse.ParseException;
import com.parse.ParseObject;
import com.parse.ParseQuery;

import android.app.Activity;
import android.app.DownloadManager.Query;
import android.content.Context;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.AutoCompleteTextView;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ListView;
import android.widget.TextView;

public class FridgeRecipe extends Activity 
{
    ListView ingsListView;
    EditText ingredientEt;
    TextView mainTitleTv, endTileTv;
    Button addingBtn, searchBtn, removeBtn;
    ArrayList<IngrdientView> ingredients;
    ArrayList<String>  recipeNameResults;
    final ArrayList<String> ingredientsToCheckInDB = new ArrayList<String>();
    final int idInList = 0;
    IngredientsListAdapter ila;
    AutoCompleteTextView actv;

    @Override
    protected void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_fridge_recipe);
        ingsListView = (ListView) findViewById(R.id.lIngredientsListView);
        mainTitleTv = (TextView) findViewById(R.id.fridgeRecipeTv);
        endTileTv = (TextView) findViewById(R.id.recipeFindTv);
        actv = (AutoCompleteTextView)findViewById(R.id.autoCompleteTextView1);
        addingBtn = (Button) findViewById(R.id.ingAddBtn);
        searchBtn = (Button) findViewById(R.id.recFindBtn);
        removeBtn = (Button) findViewById(R.id.removeButton);
        ingredients = new ArrayList<IngrdientView>();
        recipeNameResults = new ArrayList<String>();
        ila = new IngredientsListAdapter(this, ingredients, ingsListView);
        ingsListView.setAdapter(ila);
        addingBtn.setOnClickListener(new View.OnClickListener() 
        {

            @Override
            public void onClick(View v) 
            {
                ila.clear();
                String ingredient = actv.getText().toString().toLowerCase();
                ingredientsToCheckInDB.add(ingredient);
                ingredients.add(new IngrdientView(ingredient, idInList));
                actv.setText("");
                ila.notifyDataSetChanged();
            }
        });


        searchBtn.setOnClickListener(new View.OnClickListener() 
        {


            @SuppressWarnings("unchecked")
            @Override
            public void onClick(View v) 
            {
                for(int i = 0 ; i <ingredientsToCheckInDB.size(); i++)
                {
                    Log.i("item:   !!!", ""+ingredientsToCheckInDB.get(i).toString());
                }
                Log.i("-----------", ""+ingredientsToCheckInDB.size());

                ParseQuery<ParseObject> _query = ParseQuery.getQuery("RecipesNewDb");

                _query.whereContains("IngredientsForSearch", "water");
                _query.findInBackground(new FindCallback<ParseObject>() 
                        {

                    @Override
                    public void done(List<ParseObject> objects, ParseException e) 
                    {
                        if(e==null)
                        {
                            for(int  i = 0 ; i <objects.size() ; i ++)
                            {
                                Log.i("objs ---->","->");//""+objects.get(i).toString());
                            }
                        }
                        else
                        {
                            Log.i("eeeeeeeeee", ""+e);
                        }

                    }
                        });
                //              _query.whereEqualTo("RecipeName", "Lemon Ice Cream");
                //              _query.getFirstInBackground(new GetCallback<ParseObject>() 
                //                      {
                //                  public void done(ParseObject object, ParseException e) 
                //                  {
                //                      if (object == null) {
                //                          Log.d("score", "The getFirst request failed.");
                //                      } else {
                //                          Log.d("score", "Retrieved the object.");
                //                          Log.i("value: ", ""+object.getString("RecipeName"));
                //                      }
                //                  }
                //                      });




                ParseQuery<ParseObject> query = ParseQuery.getQuery("RecipesNewDb");
                query.whereContainsAll("IngredientsForSearch",  ingredientsToCheckInDB);
                query.findInBackground(new FindCallback<ParseObject>() 
                        {

                    @Override
                    public void done(List<ParseObject> objects, ParseException e) 
                    {
                        Log.i("objects:  ", "" +objects.size());
                        // recipeNameResults.add(objects.toString());
                        //if (e == null)
                        //{
                        for (int i = 0; i < objects.size(); i++) 
                        {
                            recipeNameResults.add(objects.get(i).get("RecipeName").toString());
                            Log.i("name:  ",objects.get(i).get("RecipeName") + "");
                        }
                        //}
                        //else {
                        Log.i("e________", "" + e);
                        //}
                    }
                        });
            }
        });

    }

}

Answer 1

我遇到了类似的问题，我试图获得一个我保存在解析中并放入文本视图的String数组（我还将用户用户名保存在单独的密钥中），这是一个解决方案：

**

存储数组

public class names extends ActionBarActivity {
   List<String> list = new ArrayList<String>();

@Override
 protected void onCreate(Bundle savedInstanceState) {
 super.onCreate(savedInstanceState);
 setContentView(R.layout.activity_names);

   //the button to store the array of strings
  mInterests.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
       // the empty string is added because of the querying method   
       //  i used in getting back the array.
       list.add("");

         // to get the user username and store in a String
        ParseUser parseUser = ParseUser.getCurrentUser();
        String userName = parseUser.getUsername();

      //save the String array
        ParseObject parseObject= new ParseObject("Names");
         // Your list can contain more than the empty String
        parseObject.put("StringArray", list);
        parseObject.put("name", userName);
       parseObject.saveInBackground();
    }
  }

**

从解析中获取字符串数组并放入textView

      public class MainActivity extends ActionBarActivity {
  @Override
   protected void onCreate(Bundle savedInstanceState) {
     super.onCreate(savedInstanceState);
     setContentView(R.layout.main_Activity);
      tvInterests = (TextView)findViewById(R.id.userInterests);

        ParseUser parseUser = ParseUser.getCurrentUser();
     currentuserUsername = parseUser.getUsername();


      List list1 = new ArrayList();
     list1.add("");

     ParseQuery<ParseObject> query = ParseQuery.getQuery("Names");
     query.whereEqualTo("name", currentuserUsername);
     query.whereContainedIn("StringArray", list1);

    query.getFirstInBackground(new GetCallback<ParseObject>() {
    @Override
    public void done(ParseObject parseObject, ParseException e) {
        if(e == null){
            if(parseObject != null){  JSONArray userInterest=parseObject.getJSONArray("StringArray");

                try {
                    String[] resultingArray = userInterest.join(",").split(",");
                   // tvInterest.setText(Arrays.toString(resultingArray));
                    tvInterest.setText(Arrays.toString(resultingArray).replaceAll("\\[|\\]", ""));
                } catch (JSONException e1) {
                    e1.printStackTrace();
                    AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
                    builder.setMessage(e1.getMessage());
                    builder.setTitle("Error changing json array");
                    builder.setPositiveButton("OK", new DialogInterface.OnClickListener() {
                        @Override
                        public void onClick(DialogInterface dialog, int which) {
                            // remove the alert dialog
                            dialog.dismiss();

                        }
                    });
                    AlertDialog dialog = builder.create();
                    dialog.show();

                }



            }else {
                // there was an error
            }
        }else{
            //there was an error
        }
    }
});
   }
}

老实说，我希望它有所帮助。

Answer 2

我看到没有人为你回答这个问题，所以这是一个充满希望的答案：

如Parse文档所述，你应该使用whereEqualTo（key，value）而不是 whereContains（key，value）来搜索数组字段。

官方文件是 - ＆gt; https://parse.com/docs/relations_guide，示例如下

” 假设在这个游戏应用程序中，我们希望确保每个Game对象都与Parse User相关联。我们可以这样实现：

将对象添加到数据库

ParseObject game = new ParseObject("Game");
game.put("createdBy", ParseUser.getCurrentUser());

从数据库表的array类型字段

中检索对象

ParseQuery<ParseObject> gameQuery = ParseQuery.getQuery("Game");
gameQuery.whereEqualTo("createdBy", ParseUser.getCurrentUser());

当我尝试检索用户正在接收的所有消息以在列表中显示时，这对我来说非常有用。我希望它可以帮助你找到一些饮用水。（不）口渴，我的朋友：）

检查解析数组列是否包含某些值

2 个答案: