如何在MVC4中的View中选择新值

Question

这是我的方法

public PartialViewResult GetAllClassroom()
    {
        Guid entityId = new Guid();
        var searchClassRooms = from m in db.Forms
                               where m.FormTypeEnumId == "CLASSROOM" && m.FormTitle.ToUpper() == "Add a Classroom".ToUpper() && m.EntityId == entityId
                               join fs in db.FormSubmits on m.FormId equals fs.FormId
                               select new
                               {
                                   FormId = m.FormId,
                                   FormSubmitsId = fs.FormSubmitId,
                                   FormTitle = fs.FormTitle,
                                   CreatedOn = fs.CreatedOn
                               };

        return PartialView("_getClassRoom", searchClassRooms.Distinct().OrderByDescending(s => s.CreatedOn).ToList());
    }

我想在我的视图中传递这些值但是它说没有传递给视图的模型...视图如下

@foreach (var item in Model)
{
   <p>FormId: </p> @item.FormId
   <p>FormSubmitsId : </p> @item.FormSubmitsId 
   <p>FormTitle : </p> @item.FormTitle 
   <p>CreatedOn : </p> @item.CreatedOn 
}

我做错了什么？

Answer 1

执行以下操作

1-创建一个类Result，如下所示

public class Result
{
    public int FormId{get; set;}
    public int FormSubmitsId{get; set;}
    public string FormTitle{get; set;}
    public DateTime CreatedOn{get; set;}
}

2-将控制器中的代码更改为以下

public PartialViewResult GetAllClassroom()
    {
        Guid entityId = new Guid();
        var searchClassRooms = from m in db.Forms
                               where m.FormTypeEnumId == "CLASSROOM" && m.FormTitle.ToUpper() == "Add a Classroom".ToUpper() && m.EntityId == entityId
                               join fs in db.FormSubmits on m.FormId equals fs.FormId
                               select new Result // adding the Result to be strongly typed view
                               {
                                   FormId = m.FormId,
                                   FormSubmitsId = fs.FormSubmitId,
                                   FormTitle = fs.FormTitle,
                                   CreatedOn = fs.CreatedOn
                               };

        return PartialView("_getClassRoom", searchClassRooms.Distinct().OrderByDescending(s => s.CreatedOn).ToList());
    }

3-将您的观点修改为以下

@model IEnumerable<YourSolutionName.Models.Result> // you might change the path of your Result class

@foreach (var item in Model)
{
   <p>FormId: </p> @item.FormId
   <p>FormSubmitsId : </p> @item.FormSubmitsId 
   <p>FormTitle : </p> @item.FormTitle 
   <p>CreatedOn : </p> @item.CreatedOn 
}

<强> EIDTED

保持您的设置，这意味着将匿名对象传递给视图

然后你可以用这种方式使用反射渲染视图

@model dynamic
@{
    var type = Model.GetType().GetProperties();
}
@foreach (System.Reflection.PropertyInfo property in type)
{
    <p>@(property.Name) :</p>@property.GetValue(Model, null)
}

希望这会对你有所帮助