Question

在分割电子邮件ID时获取此按摩[Ljava.lang.String;@776a35. 为什么我不明白。

        String[] For_split_email=email.split("[@._]");
        for (int j = 0; j <= For_split_email.length - 1; j++) {
        System.out.println("splited emails----------"+For_split_email[j]);
         }

Answer 1

在java中，您无法打印数组（这是您尝试时获得的输出）。您必须使用Arrays.toString()。

String[] For_split_email=email.split("[@._]");
System.out.println("splited emails----------"
    + Arrays.toString(For_split_email));

我很确定您发布的代码不是产生该输出的代码。

Answer 2

您的代码非常适合我。但它在for循环中应该是j <= For_split_email.length - 1。

    String email = "test@test.de";
    String[] For_split_email = email.split("[@._]");
    for (int j = 0; j <= For_split_email.length - 1; j++)
    {
        System.out.println("splited emails----------" + For_split_email[j]);
    }

输出：

splited emails----------test
splited emails----------test
splited emails----------de

Answer 3

我不确定您给出的电子邮件内容。如果您想按照问题中提到的那样拆分电子邮件，请尝试这样做，

    String email ="test@gmail.com";
    String[] For_split_email=email.split("[@._]");
    for (int j = 0; j <= For_split_email.length - 1; j++) {
       System.out.println("splited emails----------"+For_split_email[j]);
     }

Answer 4

你可以尝试

String str = "example@email.com";
String split_first = str.substring(0,str.indexOf("@"));
String split_second = str.substring(str.indexOf("@")+1);

或

String email = "example@email.com";
String[] For_split_email=email.split("[@|\\.|_]");
        for (int j = 0; j <= For_split_email.length - 1; j++) {
        System.out.println("splited emails----------"+For_split_email[j]);
         }
    }

Answer 5

试试吧

String email = "raju@gamil.com";
String[] For_split_email = email.split("[@._]");
for (int j = 0; j <= For_split_email.length - 1; j++)
{
    System.out.println("splited emails data----------" + For_split_email[j]);
}

如何在java中拆分电子邮件ID

5 个答案: