Question

我使用了以下查询

SELECT COUNT(client_mac) AS total_users 
FROM `social_user` 
WHERE social_network ='TWuser' 
GROUP BY client_mac HAVING total_users > 1

运行此查询后，我得到了这个结果

Please click here to see my result

但我需要理解我的＆＃39; total_users＆＃39;列，所以我的输出应该是

total_users: **49**

对不起我的英语，我没有足够的声誉来附上图片，这就是我添加链接的原因

Answer 1

我认为这可能会对你有所帮助

select count(client_mac) as total_user,client_mac 
from social_user
where social_network = 'TWuser'
GROUP BY client_mac`

此查询将为每个用户带来总数而不是所有用户。小提琴是here

Answer 2

我想我终于明白了你的目标。

SELECT social_network, count(*) as total_users
FROM social_user
INNER JOIN  (
  SELECT client_mac FROM social_user
  GROUP BY client_mac HAVING count(*) > 1
) as src ON src.client_mac = social_user.client_mac
GROUP BY social_network

因此，子查询应该获取所有重复的client_macs，然后查询将按社交网络组织每个条目。

我预见的问题是，如果一个client_mac存在多个社交网络。

Answer 3

尝试此查询 -

SELECT SUM(total_users) as total_usr_sum from (SELECT COUNT(client_mac) AS total_users FROM `social_user` WHERE social_network ='TWuser' GROUP BY client_mac HAVING total_users > 1) as sum

Answer 4

只需在查询中将COUNT(client_mac)替换为SUM(total_users)

如何在mysql查询中计数后对列进行求和

4 个答案: