我正在尝试下棋。到目前为止,我只使白色的棋子可以移动(你可以通过将它们拖到你想要的地方来移动它们)。但是,只有第一步才有效。为什么会这样?我用
$(".piece").mousedown(function(){}
,但只调用一次。
答案 0 :(得分:1)
问题是$("#" + tileFn).append($("#" + tileIn).html());
,它创建了一个新的piece
元素,未附加mousedown处理程序。
一种解决方案是使用事件去除标记,或者不是创建新元素,只需移动现有元素,如
function parent(element) {
var parentID = $(element).parent().attr("ID");
var parentClass = $(element).parent().attr("class");
var parentType = $(element).parent().get(0).nodeName;
if (parentID != null) {
return ("#" + parentID);
} else if (parentClass != null) {
return ("." + parentClass);
} else {
if (parentType.toLowerCase() == "body") {
parentType = document;
return parentType;
} else {
return parentType;
}
}
}
var dimensions = 600; // must be divisible by 8
var tile1 = "<div class='tile tile1' id='";
var tile2 = "<div class='tile tile2' id='";
var end = "'></div>";
var multiplicity = "";
var tileIn = "";
var tileFi = "";
var classes = "";
var color = "";
var type = "";
var possible = [];
$(document).ready(function() {
//setup start
for (var i = 0; i < 4; i++) {
for (var j = 0; j < 4; j++) {
row = i * 2 + 1;
column = j * 2 + 1;
$("#container").append(tile1 + row + column + end + tile2 + row + (column + 1) + end);
}
for (var k = 0; k < 4; k++) {
row = i * 2 + 2;
column = k * 2 + 1;
$("#container").append(tile2 + row + column + end + tile1 + row + (column + 1) + end);
}
}
$("#container").css({
height: dimensions,
width: dimensions
});
$(".tile").css({
height: dimensions / 8,
width: dimensions / 8
});
$(".piece").css({
height: dimensions / 8,
width: dimensions / 8
});
$("<div class='b p piece'><img src='bp.icns' height='69'></div>").appendTo("#21, #22, #23, #24, #25, #26, #27, #28");
$("<div class='b r piece'><img src='br.icns' height='69'></div>").appendTo("#11, #18");
$("<div class='b n piece'><img src='bn.icns' height='69'></div>").appendTo("#12, #17");
$("<div class='b b piece'><img src='bb.icns' height='69'></div>").appendTo("#13, #16");
$("<div class='b k piece'><img src='bk.icns' height='69'></div>").appendTo("#14");
$("<div class='b q piece'><img src='bq.icns' height='69'></div>").appendTo("#15");
$("<div class='w p piece'><img src='wp.icns' height='69'></div>").appendTo("#71, #72, #73, #74, #75, #76, #77, #78");
$("<div class='w r piece'><img src='wr.icns' height='69'></div>").appendTo("#81, #88");
$("<div class='w n piece'><img src='wn.icns' height='69'></div>").appendTo("#82, #87");
$("<div class='w b piece'><img src='wb.icns' height='69'></div>").appendTo("#83, #86");
$("<div class='w q piece'><img src='wq.icns' height='69'></div>").appendTo("#84");
$("<div class='w k piece'><img src='wk.icns' height='69'></div>").appendTo("#85");
//setup end
$(".piece").mousedown(function() {
tileIn = parent($(this)).substr(1, 2);
classes = $(this).attr("class");
color = classes.charAt(0);
type = classes.charAt(2);
y = tileIn.charAt(0);
x = tileIn.charAt(1);
//white start
if (color == "w") {
//white pawn start
if (type == "p") {
if (y == "7") {
possible = ["6" + x, "5" + x];
} else {
possible = [(y - 1) + x];
}
return;
}
//white pawn end
//
else if ("a" == "b") {
}
}
//white end
//black start
else {
}
//white end
});
$(".tile").mouseup(function() {
tileFn = $(this).attr("id");
if (jQuery.inArray(tileFn, possible) !== -1 && $(this).is(':empty')) {
$("#" + tileFn).append($("#" + tileIn).contents());
} else {}
possible = [];
});
});
* {
user-drag: none;
-moz-user-select: none;
-webkit-user-drag: none;
}
#container {
margin: 0 auto;
border: 1px solid gray;
}
.tile {
float: left;
}
.tile1 {
background-color: white;
}
.tile2 {
background-color: rgba(0, 0, 0, 0.58);
}
.piece {
padding: 3px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.10.4/jquery-ui.min.js"></script>
<link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.10.4/themes/smoothness/jquery-ui.css">
<div id="container"></div>
答案 1 :(得分:0)
选择器$(".piece")
仅在您执行语句时选择其上有pices的字段。当棋子在棋盘上移动时,你必须将这个功能添加到字段中。
因此,mouseup函数应该可以为新字段上的片段设置回调。