Question

我对java很新，而且只是编程。我正在尝试制作一个简单的故事游戏＆＃34;。我希望程序重新开始，我评论了＃34;再次开始点if walk.equals("b")（第二次）＆＃34;

这是我的代码：附：抱歉，如果写得不好

import java.util.*;

public class leikur1 {

   public static void main(String[] args) { 

     Scanner scan = new Scanner(System.in);
     System.out.println("|---------Welcome to the adventure------------|"); 
     System.out.println("Please enter Name"); // inputs name
     String nafn = scan.nextLine();
     nafn = nafn.toLowerCase();

     System.out.println("Gender, male or female");
     String kyn = scan.nextLine();
     kyn = kyn.toLowerCase();
        while((!kyn.equals("male")) && (!kyn.equals("female")) )  //bara haegt ad velja male eda female
        {
          System.out.println("That is not valid input" );
          kyn = scan.nextLine();
          kyn = kyn.toLowerCase();
        }


     System.out.println("Are you ready for the adventure"); 
     String leikur = scan.nextLine();
     leikur = leikur.toLowerCase(); 
         while((!leikur.equals("yes")) && (!leikur.equals("no")) )  //impossible to input something else than male or female
         {
           System.out.println("That is not valid input" );
           leikur = scan.nextLine();
           leikur = leikur.toLowerCase();
         } 
     if(leikur.equals("no"))
          {
            System.out.println("Thank you anyway"); //if input = no program ends
           }


     // if input = yes the game begins
     else
          {
           System.out.println("Write Start to begin or Quit to exit"); 
     String start = scan.nextLine();
     start = start.toLowerCase();

     String gender;  
     if(kyn.equals("male"))
          {
          gender = "he"; 
          }
    else
    {
      gender = "she";
              }



     while((!start.equals("start")) && (!start.equals("quit")) )
     {
       System.out.println("That is not valid input" );
       start = scan.nextLine();
       start = start.toLowerCase();
     }


     if(start.equals("start")) 
     {
     System.out.println("Walking instructions: left - l    right - r     forward - f      back -  b    down - d     up - u\n");  
     System.out.println(nafn + " is in a abandoned house late at night, stuck in the basement with no light.\n");
     System.out.println("In wich way should " + gender + " go to find his way to the stairs?"   ); **// starting again point if walk.equals("b") (second time)**
     String walk = scan.nextLine();
     walk = walk.toLowerCase();

     //////////
     while((!walk.equals("f")) && (!walk.equals("b")) ) // not possible bcus of walls or no stairs
     {
       System.out.println("That is not possible" );
       walk = scan.nextLine();
     }


     if(walk.equals("f"))
          {
           System.out.println("Great choice, " + gender + " found the stairs right away. Should"+gender+" go upstairs or go back?" );
          }

     else if (walk.equals("b"))
          {
           System.out.println("Oh boy! " + nafn +" got stuck in a beartrap and died... GAME OVER" );
          }
   /////////

     walk = scan.nextLine();
     while(!walk.equals("u") && !walk.equals("b") )
     {
       System.out.println("That is not possible" );
       walk = scan.nextLine();
     }


     if(walk.equals("u"))
     {
     System.out.println("Excelent!" + nafn + " is now upstairs" );
     }

     **else if(walk.equals("b") )
     {
     System.out.println("Now " + nafn + " is at stage 1 again" );
     }**
     //////////////



     // code 4 the game should be here above
     }
     else if(start.equals("quit"))
     {
     System.out.println("Thank you anyway");
     }

    }        

  }
}

Answer 1

如果您只想重复内容，while循环就足够了

boolean continue = true;

while(continue)
{
   else if(walk.equals("b") )
   {
       System.out.println("Now " + nafn + " is at stage 1 again" );
       continue = true;
   }
   else if(start.equals("quit"))
   {
       System.out.println("Thank you anyway");
       continue = false;
   }
}

我使用变量continue的原因是为了更好地说明while循环。你也可以使用while(true)，这通常会永远循环。要跳到使用continue;的下一次迭代的开始并突破，您可以使用break

while(true)
{
   else if(walk.equals("b") )
   {
       System.out.println("Now " + nafn + " is at stage 1 again" );
       continue;
   }
   else if(start.equals("quit"))
   {
       System.out.println("Thank you anyway");
       break;
   }
}

如果您真的想要将您的编码提升到新的水平，您可以采用更加数据驱动的方法，并拥有一个数据模型来定义您的游戏。以下是xml

中的示例数据模型

<Places>
    <Place name="YourRoom" text="You are in your room. Where would you like to go?">
        <Option text="Enter the hallway." result="Hallway"></Option>
    </Place>
    <Place name="Hallway" text="You are in the hallway. Where would you like to go?">
        <Option text="Go to your room" result="YourRoom"></Option>
    </Place>
</Places>

然后你就像这样编写你的程序

<强>伪代码：

xmlElement currentRoom = // get starting element

while(true)
{
    print(currentRoom.Attributes[text])
    for(int i=0; i<currentRoom.Elements.length; i++)
    {
        print(currentRoom.Elements[i] + "type " + i+1;
    }
    int choice = getInt();
    int result = currentRoom.Elements[choice].result;
    currentRoom GetElementWithName(result);   
}

Answer 2

您应该学习Java，OOP和其他基础构造。如果你真的坚持，你可以使用labels（说实话，自结构化编程出现以来，六十年代人们不再尝试使用GOTO ......但是如果你想在面试中失败，请继续; - ））

// ...
// label is your label, you can use any text
label:{ 
  // ...
  // here is your GOTO
  break label;
}

旁注：它就像一个魅力，但请不要这样做（或者至少不要说我是那个告诉你标签的人）！

需要在java中的某个点重新开始

2 个答案: