Question

我正在制定学生时间表，但我遇到了问题。我需要有本周和下周的一系列日子。因此，如果今天是星期二11.11，我需要以某种方式获得星期一10.11星期二11.11星期三12.11星期四13.11星期五星期四14.11，以及下周的同一天日期。这个我需要在我的程序中执行这样的功能，当用户可以选择一周中的任何一天并在这一天设置他的日程安排。我在堆栈溢出时到处查看，但所有解决方案都不准确。你能帮助我吗？这是我的一些尝试。

NSDate *now = [NSDate date];

NSCalendar *calendar = [NSCalendar currentCalendar];

NSDate *beginningOfThisWeek;
NSDate *beginningOfNextWeek;

NSTimeInterval durationOfWeek;
[calendar setFirstWeekday:3];
[calendar rangeOfUnit:NSCalendarUnitWeekOfMonth
            startDate:&beginningOfThisWeek
             interval:&durationOfWeek
              forDate:now];

beginningOfNextWeek = [beginningOfThisWeek dateByAddingTimeInterval:durationOfWeek];


NSDate *date = beginningOfThisWeek;
NSMutableArray *dateArray = [@[] mutableCopy];

while (![beginningOfNextWeek compare:date]  == NSOrderedSame) {
    [dateArray addObject:date];
    NSDateComponents *comps = [calendar components:NSUIntegerMax fromDate:date];
    comps.day +=1;
    date = [calendar dateFromComponents:comps];

}
NSLog(@"%@",dateArray);
NSLog(@"%@",now);

但在日志中我会得到类似的内容：

2014-11-11 18:37:29.479 StudentSchedule[3964:436389] (
    "2014-11-10 22:00:00 +0000",
    "2014-11-11 22:00:00 +0000",
    "2014-11-12 22:00:00 +0000",
    "2014-11-13 22:00:00 +0000",
    "2014-11-14 22:00:00 +0000",
    "2014-11-15 22:00:00 +0000",
    "2014-11-16 22:00:00 +0000"

我有约会，但是7，我没有工作日的名字，这非常重要。我知道我的问题很简单，但我厌倦了寻找正确的答案。

Answer 1

好的，所以说你在某一天打开应用程序。

您希望该周的所有工作日（周一至周五）以及下周的所有工作日。

右...

- (void)getDays
{
    NSArray *days = @[];

    NSDate *currentDate = [NSDate date];

    // add this week's work days to array
    days = [days arrayByAddingObjectsFromArray:[self workDaysOfWeekFromDate:currentDate]];

    NSDate *nextWeek = [self dateWeekAfterDate:currentDate];

    // add next week's work days to array
    days = [days arrayByAddingObjectsFromArray:[self workDaysOfWeekFromDate:nextWeek]];
}

- (NSDate *)dateWeekAfterDate:(NSDate *)date
{
    NSCalendar *calendar = [NSCalendar currentCalendar];

    NSDateComponents *components = [NSDateComponents new];
    components.day = 7;

    return [calendar dateByAddingComponents:components toDate:date options:0];
}

- (NSInteger)dayOfWeekFromDate:(NSDate *)date
{
    NSCalendar *calendar = [NSCalendar currentCalendar];

    NSDateComponents *components = [calendar components:NSCalendarWeekdayUnit fromDate:date];

    return components.weekday;
}

- (NSDate *)dayWithIndex:(NSInteger)dayIndex fromWeekOfDate:(NSDate *)date
{
    NSInteger dayOfWeekFromDate = [self dayOfWeekFromDate:date];

    NSInteger difference = dayIndex - dayOfWeekFromDate;

    NSDateComponents *components = [NSDateComponents new];
    components.day = difference;

    NSCalendar *calendar = [NSCalendar currentCalendar];

    return [calendar dateByAddingComponents:components toDate:date options:0];
}

- (NSArray *)workDaysOfWeekFromDate:(NSDate *)date
{
    // Sunday = 1
    // ...
    // Saturday = 7

    return @[
        [self dayWithIndex:2 fromWeekOfDate:date], // Monday
        [self dayWithIndex:3 fromWeekOfDate:date], // Tuesday
        [self dayWithIndex:4 fromWeekOfDate:date], // Wednesday
        [self dayWithIndex:5 fromWeekOfDate:date], // Thursday
        [self dayWithIndex:6 fromWeekOfDate:date]  // Friday
    ];    
}

这里有几个功能。一切都在getDays函数中完成并完成。完成后，数组days将在本周和下周的周一至周五包含NSDate对象。

当然，您可以将currentDate更改为您想要的任何日期。它始终需要currentDate的一周和currentDate之后的一周。

这将始终有效，任何日历和闰年等......

要获取日期的名称，您可以执行此操作...

NSDate *date = [NSDate date];

NSDateFormatter *df = [NSDateFormatter new];
df.dateFormat = @"EEEE";

NSString *dayName = [df stringFromDate:date];

格式EEEE表示日期名称。所以今天dayName字符串是Tuesday。

EEEE = Tuesday
EEE = Tue

你当然可以将它合并为一个功能较少的功能。但我更喜欢可读的代码。

一周工作几天

1 个答案: