这是我的代码......我需要根据他们的投票对所有参赛者进行排名......你可以看到有名单和投票数的单独数组（统计数字）......我被告知泡泡sort会工作，但我不知道如何因为冒泡排序取代内部所以如果tally [2]大于tally [1]，它将成为新的计数[1]同时名称保持与名称[1]不相同更改名称[2] ...我希望您使用基本代码，因为我是编程的总菜鸟，并且最近刚刚开始...还有，关于我如何能更好/更短地编写代码的任何建议都值得赞赏< / p>
import java.util.*;
public class FroshNight {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String dec = "0";
System.out.println("How many blocks?");
int contno = sc.nextInt();
int winner = 0;
String winname = "a";
String[] code = new String[contno];
int total = 0;
int counter = 0;
String[] contname = new String[contno];
int[] tally = new int[contno];
while (counter<contno) {
System.out.print("Name of Pair:");
contname[counter]=sc.next();
counter++;
}
counter=0;
while (counter<contno) {
System.out.println("Choose a vote code for "+ contname[counter]+"(must not be x)");
code[counter] = sc.next();
counter++;
}
boolean stop = false;
counter=0;
while(stop == false){
System.out.println("Input Vote (x to exit): ");
dec = sc.next();
if(dec.equals("x")) {
stop = true;
}
counter = 0;
while(counter<contno){
if(dec.equals(code[counter])){
tally[counter] +=1;
counter = contno;
}
counter++;
}
}
//>> aft. else
counter = 0;
while(counter<contno){
total += tally[counter];
counter++;
;
}
counter=0;
while(counter<contno){
if(tally[counter]>winner){
winner = tally[counter];
winname = contname[counter];
}
counter++;
}
System.out.print("The Winner is: "+ winname +" - "+winner );
System.out.println("("+((double)winner/total)*100+"%)");
counter = 0;
while (counter<contno) {
System.out.print(contname[counter]+" - Score:");
System.out.print(tally[counter]);
System.out.println("("+((double)tally[counter]/total)*100+"%)");
counter++;
}
//>>> end while
// add rankings here^^
}
}