我使用Mono在Ubuntu 12.04下运行C#服务器,代码如下:
while (true)
{
Console.WriteLine("Socket ready...");
using (Socket handlerSocket = listenerSocket.Accept())
{
Console.WriteLine("New request...");
BackgroundWorker newBackgroundWorker = new BackgroundWorker();
byte[] buffer = new byte[1024];
Console.WriteLine("Buffer allocated...");
handlerSocket.Receive(buffer);
//newBackgroundWorker.DoWork += (s, o) =>
//{
using (Socket Sender = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp))
{
Console.WriteLine("Buffer received...");
string request = Encoding.Unicode.GetString(buffer);
Console.WriteLine("New request from : {0} /t Request : {1}", ((IPEndPoint)handlerSocket.RemoteEndPoint).Address.ToString(), request);
if (request.Contains("$GetBattleList"))
{
//Chain of if's and else's continues
//The following else if is the only case being tested
else if (request.Contains("$GetZeroBasedProfile"))
{
Console.WriteLine("Sending profile...");
Sender.Connect(handlerSocket.RemoteEndPoint); //Fails here due to not being able to reach the client application, throws a timeout exception
Sender.SendFile(_profileLocation);
}
else Console.WriteLine("Invalid request. Ignoring...");
}
}
}
服务器能够接收客户端请求,但无法响应,因为它无法每次都连接。 我在代码中遗漏了什么或在这里有其他工作吗?
答案 0 :(得分:3)
您需要声明的附加套接字Sender
是不必要的。您从handlerSocket
收到的listenerSocket.Accept()
已经是您可以用来与客户进行通信的套接字。
答案 1 :(得分:1)
当您使用服务器套接字接受连接时,您得到的是连接到客户端的套接字。您不必创建要连接的新套接字(事实上,您不能)。因此,请使用Sender
:
handlerSocket
handlerSocket.SendFile(_profileLocation);