Question

我有这个PHP文件：

 <?php
 //Get data from instagram api
 $keyword = $_GET['keyword'];
 if(!isset($_GET['count'])) $count = 20;
 else $count = $_GET['count'];

 //Query need client_id or access_token
 $query = array(
'client_id' => '8c81a425a76340a79aa66cb88aa74c89',
'count'     => $count
 );
 $url = 'https://api.instagram.com/v1/users/search?q='.$keyword.'&'.http_build_query($query);

 try {
$curl_connection = curl_init($url);
curl_setopt($curl_connection, CURLOPT_CONNECTTIMEOUT, 30);
curl_setopt($curl_connection, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl_connection, CURLOPT_SSL_VERIFYPEER, false);

//Data are stored in $data
$data = curl_exec($curl_connection);
curl_close($curl_connection);
echo $data;
 } catch(Exception $e) {
return $e->getMessage();
 }
 ?>

接受关键字并显示来自Instagram API的所有用户信息。

我想创建一个html文件，其中有一个带有关键字的文本字段并将其发送到php文件并检索并显示前20个结果

假设这是我的html文件

 <!DOCTYPE html>
 <html>

 <head>
 <meta charset="UTF-8">
 <title>Instagram Search</title>
 </head>
 <script>
         //here will be the function 
 </script>
 <body>

 <header>
 <div align="left">
 <h3>Instagram User Search</h3>
 </div>
 <div align="center">
 <form>
 Search:<input type="text" name="keyword">
 <input type="submit" value="Search">
 </form>
 </div>
 </header>

 <section>
 <h1></h1>
 <div class="images">
 <img src=""></img> // here where to retrive picture
 <h1> </h1> // here where to retrive the name of the user
 </div>
 </section>

 </body>

 </html>

我知道我会使用jquery来做这件事，但我不知道我怎么知道我需要传递＆＃34;关键字＆＃34;，来自文字领域的价值我也知道我去了通过关键字使用检索到的数据，例如，如果我有这个返回的数据：

 {"meta":{"code":200},"data":[{"username":"php","bio":"","website":"","profile_picture":"http:\/\/images.ak.instagram.com\/profiles\/anonymousUser.jpg","full_name":"Henrik Pedersen","id":"224046"},{"username":"2popetorn","bio":"The best thing you can put on your face is \"your smile\" #BEsomethingspecial","website":"http:\/\/youtu.be\/-tGIMN_27uQ","profile_picture":"http:\/\/photos-a.ak.instagram.com\/hphotos-ak-xfa1\/10632506_282561178612800_200298941_a.jpg","full_name":"\u0e15\u0e39\u0e48 \u0e20\u0e1e\u0e18\u0e23","id":"10731841"}]}

我将采用＆＃34;用户名＆＃34;的值并将其存储在字符串中，所以

我知道如何做到这一点的想法，但我不知道如何在jquery和javascript中进行编码..有人可以帮忙吗？

尝试了这个：

  <!DOCTYPE html>
  <html>
<head>
   <title>jQuery Test</title>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.9.1.js"></script>
 <script type="text/javascript">
 $(document).ready(function() {

        $("#submit").click(function(){

        $.ajax({
        url: "http://www.lamia.byethost18.com/get_info.php",
        type: "GET",
        data: {keyword: $("#keyword").val()},
        dataType: "JSON",
        success: function (jsonStr) {
            $("#result").text(JSON.stringify(jsonStr));
        }
    });

}); 

});
</script>
</head>
<body>
<div id="result"></div>
    <form name="contact" id="contact" method="get">
     keyword : <input type="text" name="keyword" id="keyword"/><br/>
    <input type="button" value="search!" name="submit" id="submit"/>
    </form>

</body>
  </html>
  </html>

它会在我的html上打印json结果字符串，如

  {"meta":{"code":200},"data":[{"username":"lama","bio":"","website":"","profile_picture":"http://images.ak.instagram.invalid/profiles/profile_42284_75sq_1353177507.jpg","full_name":"Li Shing","id":"42284"},{"username":"bekhand_lamasab","bio":"??? ?? ?? Kik : narsis.fashion ??\n????? ? ? ?? sfs : 520 k ??\n????? ??? ???? ????? ??????????? ?? \n??????????????? ?? ??? ????? ???????????","website":"","profile_picture":"http://photos-f.ak.instagram.invalid/hphotos-ak-xap1/10349797_785664258123877_321110299_a.jpg","full_name":"?????????? ??? ???????????????","id":"1085311553"},{"username":"lamarquisette","bio":"","website":"","profile_picture":"http://images.ak.instagram.invalid/profiles/profile_279115230_75sq_1378119768.jpg","full_name":"Youssef Marquis","id":"279115230"},{"username":"timlaman","bio":"NatGeo Wildlife Photographer - Filmmaker - Field Biologist. Exploring wild places, rare species, rain forests and coral reefs.\nSee more on FB:","website":"https://www.facebook.invalid/TimLamanPhoto","profile_picture":"http://images.ak.instagram.invalid/profiles/profile_195678468_75sq_1342554137.jpg","full_name":"Tim Laman","id":"195678468"},{"username":"lamamadelrap","bio":"#RIPMonkeyBlack\n??MELYMEL NO UTILIZA FACEBOOK??\n(Twitter) @MELYMELMELADA \n(RD) 809.360.9052\n(USA) 347.209.2816","website":"http://www.youtube.invalid/MelymelVEVO","profile_picture":"http://photos-g.ak.instagram.invalid/hphotos-ak-xpf1/10693447_660276060736558_41448872_a.jpg","full_name":"MelyMel #zeroDembow","id":"305872466"},{"username":"lamarctaylor","bio":"no reality is the same.","website":"","profile_picture":"http://photos-f.ak.instagram.invalid/hphotos-ak-xpa1/10731950_736068223151773_567726601_a.jpg","full_name":"lamarctaylor","id":"206461711"},{"username":"lamaisond","bio":"","website":"","profile_picture":"http://photos-g.ak.instagram.invalid/hphotos-ak-xpa1/10610996_331177297053686_1564957178_a.jpg","full_name":"","id":"1572747"},{"username":"joud_lama","bio":"?? ???? ???? ????? ?????????\nAll about my kids ????\nOur daily life in videos \n????? ???? ????? ??? ?????\n?????? ???? ???? ??????? ??????? ?? ?? ????","website":"https://m.youtube.invalid/watch?v=6PvF2TjuhQw","profile_picture":"http://images.ak.instagram.invalid/profiles/profile_812908181_75sq_1399322579.jpg","full_name":"Joud_lama","id":"812908181"},{"username":"co._lams","bio":"","website":"","profile_picture":"http://photos-h.ak.instagram.invalid/hphotos-ak-xpa1/10731956_923164217707383_1481888166_a.jpg","full_name":"Lamar","id":"940742669"},{"username":"lamarca941fm","bio":"","website":"","profile_picture":"http://images.ak.instagram.invalid/profiles/profile_1173210472_75sq_1394672048.jpg","full_name":"La Marca 94.1 FM","id":"1173210472"},{"username":"jonjonlamar","bio":"#Miami - #NYC. ????\nA Private Life is a Happy Life.. ??","website":"","profile_picture":"http://photos-e.ak.instagram.invalid/hphotos-ak-xap1/10483455_526566950776404_1475004702_a.jpg","full_name":"Jonathan Lamar Green","id":"18211272"},{"username":"lamafiabeats","bio":"?Produccion y promocion de eventos??\n?cuenta aliada @shopvipcaracas??\n?publicidad y contacto +58 4242308332","website":"","profile_picture":"http://photos-b.ak.instagram.invalid/hphotos-ak-xaf1/10731882_609733789138665_677150285_a.jpg","full_name":"la mafia lifestyle","id":"1533879744"},{"username":"marisa_lmp","bio":"???? Co-Founder : @micha_thailand\n???????????????????????-????????????\n???????????? : lmp.marisa/fon-lamapearl???\n?????: 092-2845899 , 085-389-5648 ??","website":"http://www.lamapearl-scare.invalid","profile_picture":"http://photos-f.ak.instagram.invalid/hphotos-ak-xaf1/10731597_1494940657448173_726227876_a.jpg","full_name":"??CEO of LaMaPearl scare??","id":"10083328"},{"username":"lamaterialista1","bio":"Artista, Actriz, compositora Booking: RD 829-963-3653 USA 917-743-5599 / lamaterialistabooking@gmail.invalid / sigueme en twitter @LAMATERIALISTA1","website":"http://www.youtube.invalid/LaMaterialistaVEVO","profile_picture":"http://photos-c.ak.instagram.invalid/hphotos-ak-xap1/10665318_743709879028514_706220468_a.jpg","full_name":"LA REINA DE LA CHAPA QUEVIBRAN","id":"177807899"},{"username":"lamaris87","bio":"","website":"","profile_picture":"http://photos-f.ak.instagram.invalid/hphotos-ak-xpa1/10665398_1493770557570293_1634650289_a.jpg","full_name":"Lamaris","id":"30943990"},{"username":"lamaracuchis","bio":"Animadora de La Bomba \nFashion Blogger\nBlog: http://www.carlafieldproject.invalid\nChequea mi nuevo tutorial de maquillaje \naquí ? espero lo disfruten.","website":"http://youtu.be/uLLv72vmgG4","profile_picture":"http://photos-a.ak.instagram.invalid/hphotos-ak-xfp1/891345_637029753056760_2048316896_a.jpg","full_name":"Carla Field","id":"238108076"},{"username":"lamaskeproduce","bio":"Producción de Tv y Radio,influyente,sarcástica,Yal, turista sin visa,Fan d Miley Cyrus,Dra. Polo y Dr. House.?Cuenta Alterna @lamaskeproducetv","website":"http://www.lamaskeproduce.invalid","profile_picture":"http://photos-a.ak.instagram.invalid/hphotos-ak-xap1/925887_491093354357472_430852604_a.jpg","full_name":"Jenifel Galcia Cyrus","id":"30637470"},{"username":"dalailama","bio":"Welcome to the official Instagram Account of the Office of His Holiness the 14th Dalai Lama.","website":"http://www.dalailama.invalid/","profile_picture":"http://images.ak.instagram.invalid/profiles/profile_1044003089_75sq_1391167280.jpg","full_name":"Dalai Lama","id":"1044003089"},{"username":"lamarquenyc","bio":"Creative Consultancy co-founded by Meredith Melling and Valerie Boster; la marque, get set, go!","website":"http://lamarquenyc.invalid","profile_picture":"http://images.ak.instagram.invalid/profiles/profile_1031042100_75sq_1390883999.jpg","full_name":"la marque","id":"1031042100"},{"username":"lamasat.iq","bio":"? Official Account\n| ???? ??????? ????? |\n????? ????????? ????????\n?? ???? ?????? ???? ???? ????? ?????? \nadmins\n?????????????????","website":"","profile_picture":"http://photos-a.ak.instagram.invalid/hphotos-ak-xpa1/10755896_316197498569544_758738327_a.jpg","full_name":"? ?????????? ????????? ?","id":"1360750684"}]}

这就是我想要的但我不希望它打印json字符串我想使用用户名和个人资料图片中的数据，例如我的html中的某个地方..怎么做??? < / p> 解决方法：

$(document).ready(function() {
            $("#submit").click(function(){
                $.ajax({
                    url: "http://www.lamia.byethost18.com/get_info.php",
                    data: {keyword: $("#keyword").val()},
                    dataType: 'JSON',
                    success: 
                        function(jsonStr) {
                        $('#name').text($("#keyword").val());
                        var all_results = '';
                        $.each(jsonStr.data, function(index, element){
                            all_results += '<div style="float:left; margin-left: 100px;" class="result_row">';
                            all_results += '<img src="'+element.profile_picture+'" />';
                            all_results += '<p> @' + element.username + '</p>';
                            all_results += '</div>';
                        });
                            $('#images').html(all_results);
                        }
                });
            }); 
        });

Answer 1

JSON String可以视为字典。

你应该做什么：

 success: function (jsonStr) {
        var json_result = JSON.Parse(jsonStr);
        // To get profile picture & username
        for( var i=0; i<json_result['data'].length; i++ ) {
            var username = json_result['data'][i]['username'];
            var profile_pic = json_result['data'][i]['profile_picture'];
            $("#result").text( username );
            $("#id_of_image_tag").attr( 'src',profile_pic );
        }
    }

变量包含相应的文本，使用jquery，您可以根据需要将它们添加到任何html中。

如果您要向同一个div添加文字，我还建议使用$（＆＃39;＃id＆＃39;）。append（）而不是文字。

Answer 2

您将要使用Jquery的Ajax方法将信息发送到您的脚本。（放在<script>标签内，并确保使用$(document).ready({ //jquery here });包装你的jquery代码）

$.ajax({
    url: '/point/to/php/script.php',
    type: 'GET', //or POST if you prefer
    data: { "keyword" : $("#keywordElementID").val(), /* other variables */ },
    dataType: 'JSON',
    success:
         function( returnedJSON  ){

             //use returned text here


             //to loop through data objects from API
             $.each( returnedJSON.data, function( index , dataObject ){
                 var name = dataObject.full_name;
             });                

        }
});

这只是一个让你入门的简单例子。阅读有关ajax方法here的更多信息。以及关于json here的更多信息。

这里有很多关于stackoverflow的问题，还有你的问题的答案，只是做一些更多的搜索

在JSON中搜索并使用jquery显示结果

2 个答案: