合并声明

时间:2014-11-11 13:22:23

标签: oracle merge

我正在研究合并语句,但我无法弄清楚语法。

假设我有这些表格

CREATE TABLE employee (
employee_id NUMBER(5),
first_name  VARCHAR2(20),
last_name   VARCHAR2(20),
dept_no     NUMBER(2),
salary      NUMBER(10));

INSERT INTO employee VALUES (1, 'Dan', 'Morgan', 10, 100000);
INSERT INTO employee VALUES (2, 'Helen', 'Lofstrom', 20, 100000);
INSERT INTO employee VALUES (3, 'Akiko', 'Toyota', 20, 50000);
INSERT INTO employee VALUES (4, 'Jackie', 'Stough', 20, 40000);
INSERT INTO employee VALUES (5, 'Richard', 'Foote', 20, 70000);
INSERT INTO employee VALUES (6, 'Joe', 'Johnson', 20, 30000);
INSERT INTO employee VALUES (7, 'Clark', 'Urling', 20, 90000);

CREATE TABLE bonuses (
employee_id NUMBER, bonus NUMBER DEFAULT 100);

INSERT INTO bonuses (employee_id) VALUES (1);
INSERT INTO bonuses (employee_id) VALUES (2);
INSERT INTO bonuses (employee_id) VALUES (4);
INSERT INTO bonuses (employee_id) VALUES (6);
INSERT INTO bonuses (employee_id) VALUES (7);
COMMIT;

并且仅仅为了示例我想用200 * employee_id更新所有奖金条目。这是我的发言。怎么了?

merge into bonuses b
using
  (select employee_id id, 200 bonus from employees) test
on (test.id = b.employee_id)
when matched then update set
b.bonus = test.bonus * test.employee_id

谢谢!

P.S。另请参阅我的sqlfiddle:http://sqlfiddle.com/#!4/ff425/14

1 个答案:

答案 0 :(得分:1)

merge into bonuses b
using
  (select employee_id id, 200 bonus from employee) test
on (test.id = b.employee_id)
when matched then update set
b.bonus = test.bonus * test.id;

两个小错误:

1)员工而非员工

2) test.id 而不是test.employee_id