Question

如何在ui-grid cellTemplate中显示数据时添加条件样式：我想将mofify格式显示为链接或没有链接。与Conditional cell template in ui-grid angularjs类似。

var myTemplate = '<div>{{getExternalScopes().showName(row.entity)}}</div>'

$scope.gridOptions = {
    columnDefs: [
            { field: 'code' },
            { field: 'name', cellTemplate: myTemplate},
            // field 'link
  ]
};

预期结果应该是名称是基于参数链接的链接或文本

提前致谢。

Answer 1

我制作了条件模板：

cellContainerNameLinkTemplate: 
'
<div class="ui-grid-cell-contents" 
   ng-if = "row.entity.IsSample"
   ng-class = "col.colIndex()">
   <div class = "gridnolinkpointer"> {{grid.getCellValue(row, col)}}</div>
</div>
<div ng-if = "!row.entity.IsSample">
   <div class = "nav nav-pills" ng-class = "col.colIndex()" > 
      <a class = "gridlinkpointer" ng-click = "getExternalScopes().followlink({event:$event,row:row})"> 
      {{grid.getCellValue(row, col)}}</a>
   </div>
</div>
', cellW

ui-grid angularjs中的条件单元模板类

1 个答案: