我有一个蜂巢表,
name age sal
A 45 1222
B 50 4555
c 44 8888
D 78 1222
E 12 7888
F 23 4555
我想计算年龄栏的中位数。
以下是我的方法
select min(age) as HMIN,max(age) as HMAX,count(age) as HCount,
IF(count(age)%2=0,'even','Odd') as PCOUNT
from v_act_subjects_bh;
感谢任何查询建议
答案 0 :(得分:65)
您可以使用百分位函数来计算中位数。试试这个:
select percentile(cast(age as BIGINT), 0.5) from table_name
答案 1 :(得分:-1)
double median = 0;
double term = 0;
double term1 = 0;
if (size % 2 == 1)
{
term = (size + 1 - 1) / 2;
median = term;
}
else if (size % 2 == 0)
{
term1 = (size - 1) / 2;
term1 = term1 + ((size - 1) / 2) + 1;
term1 = term1 / 2;
median = term1;
}
cout << "Median of array: " << median << endl;