我无法连接到MySQL,它在线路连接失败。打开(),我的代码有问题吗?
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using MySql.Data.MySqlClient;
namespace MySQLConnection
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
string MyConString = "SERVER=localhost:3316;" +
"DATABASE=mydb;" +
"UID=user;" +
"PASSWORD=password;";
MySqlConnection connection = new MySqlConnection(MyConString);
connection.Open();
// ...
connection.Close();
}
}
}
答案 0 :(得分:2)
您需要在连接字符串中将Port指定为单独的参数,并且密码密钥看起来像是“Pwd”而不是“Password”。
有关确切语法的帮助,请参阅connectionstrings.com。
答案 1 :(得分:2)
这是我用来通过MySql.Data.dll版本6.1.2.0连接的字符串格式
server = {0};用户ID = {1};密码= {2};数据库= {3}; port = {4}
所以你的连接字符串应该是
server = localhost; user id = user; password = password; database = mydb; port = 3316