Question

基本上我想让我的程序做的是：

new_ch = input("What channel would you like to switch to?")
if new_ch in channels:
      print("You're now on channel,", new_ch,".")
else:
       print("That's not a valid channel.")

无论我做什么，它都会在错误的分支上打印声明＆＃34;这不是有效的频道＆＃34;。有没有办法让我的程序搜索我的频道列表/元组与用户输入？我的频道列表包含变量名称ex。

Ch1 = "Ch1 - Fox News"
Ch2 = "Ch2 - PBS"

Etc.

channels = [Ch1, Ch2, Ch3, ... Ch10]

Answer 1

好的如果输入是＆＃34; ch1＆＃34;并且您希望输出为＆＃34; Ch1 - Fox News＆＃34;，那么您的if语句不正确。

因为你正在比较＆＃34; Ch1＆＃34; [＆＃39; Ch1 - Fox News＆＃39;，＆＃39; Ch2 - PBS＆＃39;]：

>>> channels = [Ch1, Ch2]
>>> channels
['Ch1 - Fox News', 'Ch2 - PBS']

所以要纠正这个问题，你需要使用字典，这里是如何：

Ch1 = "Ch1 - Fox News"
Ch2 = "Ch2 - PBS"
channels = {"CH1":Ch1,"CH2": Ch2}
new_ch = input("What channel would you like to switch to?")
What channel would you like to switch to?"ch1"
if new_ch.upper() in channels:
    print("You're now on channel,", channels[new_ch.upper()],".")
else:
    print("That's not a valid channel.")


 ("You're now on channel,", 'Ch1 - Fox News', '.')

上层函数只是与案例无关。

更新

随机化：

elif choice == "2":
    ch = random.choice(channels.keys())
    print("You're now on channel", channels[ch],".")

打印频道列表：

elif choice == "1":
    print("\n")
    for item in channels:
        print(channels[item])

如何检查列表/元组中的用户输入？

1 个答案: