Question

编写一个java程序，询问用户他/她的姓名，年龄和薪水（双倍）。遵循输入/输出格式。

以下对话应在屏幕上显示为输出，您将在其中输入姓名，年龄和工资的值。

假设您的输入是：

约翰

22

500 预期产出：

您好。你叫什么名字？你好，约翰！你几岁？所以你22岁？那根本不老！你为约翰做了多少？

500.0！我希望每小时而不是每年！ LOL！

我试着像这样解决

import java.util.Scanner; 
class Enquiry
{ 
 public static void main(String args[])
 { 
  Scanner scanner=new Scanner(System.in); 
  do{ 
     System.out.println("Hello. What is your name?"); 
     string name1 = scanner.nextString(); 
    }
  while(name1 != null) 
    { 
     System.out.println("Hi" +name1 "! How old are you?"); 
     int age = scanner.nextInt(); 
    } 
  while(age != null) 
     { 
     System.out.println("So you're" +age "eh? That's not old at all!");                     System.out.println("How much do you make John?"); 
     double salary = scanner.nextDouble(); 
     }
  while(salary != null)
    { 
     System.out.println(+salary"! I hope that's per hour and not per year! LOL!"); 
     } 
  } 
}

任何人都可以帮助我解决这个问题以及我所犯的错误谢谢，非常感谢您的帮助

Answer 1

有很多错误，比如

1。）不需要do - while loops。

2.。）字符串与+运算符连接，在system.out.println()语句中缺失。

3。）string name1，S应为大写，String是一个java关键字，指的是数据类型。

public static void main(String args[]) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Hello. What is your name?");
        String name1 = scanner.nextLine();
        System.out.println("Hi" + name1 + "! How old are you?");
        int age = scanner.nextInt();
        System.out.println("So you're" + age + "eh? That's not old at all!");
        System.out.println("How much do you make John?");
        double salary = scanner.nextDouble();
        System.out.println(+salary + "! I hope that's per hour and not per year! LOL!");
    }

<强>输出

Hello. What is your name?
John
HiJohn! How old are you?
22
So you're22eh? That's not old at all!
How much do you make John?
500
500.0! I hope that's per hour and not per year! LOL!

java输入必须从客户获取，它必须以顺序方式

1 个答案: