Question

我正在尝试安装php代码嗅探器。我已经设法达到跑步后的地步 php /Users/ryanfernandes/pear/bin/phpcs --version它显示信息。但是当我尝试通过

运行代码嗅探器时

php /Users/username/pear/bin/phpcs /Users/username/development/htdocs/test.php 
PHP Warning:  fwrite() expects parameter 1 to be resource, boolean given in /Users/username/pear/share/pear/PHP/CodeSniffer/Reporting.php on line 155

Warning: fwrite() expects parameter 1 to be resource, boolean given in /Users/username/pear/share/pear/PHP/CodeSniffer/Reporting.php on line 155
PHP Warning:  stream_get_meta_data() expects parameter 1 to be resource, boolean given in /Users/username/pear/share/pear/PHP/CodeSniffer/Reporting.php on line 206

Warning: stream_get_meta_data() expects parameter 1 to be resource, boolean given in /Users/username/pear/share/pear/PHP/CodeSniffer/Reporting.php on line 206
PHP Warning:  file_get_contents(): Filename cannot be empty in /Users/username/pear/share/pear/PHP/CodeSniffer/Reporting.php on line 208

Warning: file_get_contents(): Filename cannot be empty in /Users/username/pear/share/pear/PHP/CodeSniffer/Reporting.php on line 208
PHP Warning:  fclose() expects parameter 1 to be resource, boolean given in /Users/username/pear/share/pear/PHP/CodeSniffer/Reporting.php on line 209

Warning: fclose() expects parameter 1 to be resource, boolean given in /Users/username/pear/share/pear/PHP/CodeSniffer/Reporting.php on line 209

任何帮助都会非常感激。

由于

Answer 1

从错误消息中，您看起来正在使用PHP_CodeSniffer版本1.5.4。 PHP_CodeSniffer使用tmpfile（）函数创建临时文件。可以通过运行以下命令找到它创建的目录：

php -r 'echo sys_get_temp_dir().PHP_EOL;'

确保允许您写入该目录，因为tmpfile（）方法显然返回FALSE，如果目录不可写，则最常发生这种情况。

在Mac上发出运行代码嗅探器的问题

1 个答案: