我正在尝试为每行获取最新的CreationTime和Value，但我为每个条件获取了多行。有人可以帮忙吗？
这是我的代码和结果：
谢谢
SELECT DISTINCT
a.PatientAccountID
,e.FindingAbbr
,e.Value
,e.CreationTime
FROM
PatientVisit a with (nolock)
INNER JOIN
Assessment d with (nolock) ON a.PatientVisit_oid = d.PatientVisit_oid
INNER JOIN
Observation e with (nolock) ON e.AssessmentID = d.AssessmentID
WHERE
a.PatientAccountID = '11'
AND a.VisitTypeCode='IP'
AND a.VisitEndDateTime is null
AND e.Value != ''
AND e.FindingAbbr IN ('A_IV1 Site', 'A_IV2 Site', 'A_IV3 Site', 'A_IV4 Site')
AND EXISTS
(SELECT DISTINCT Max(e.CreationTime)
FROM Observation e with (nolock))
Order by a.PatientAccountID
我的结果如下：
PatientAccountID FindingAbbr Value CreationTime
11 A_IV1 Site L Forearm 11/10/2014 9:47
11 A_IV1 Site L Forearm 11/10/2014 1:40
11 A_IV1 Site L Forearm 11/9/2014 18:18
11 A_IV4 Site L Forearm 10/31/2014 20:57
11 A_IV4 Site L Forearm 10/31/2014 10:26
11 A_IV4 Site L Forearm 10/30/2014 22:31
11 A_IV4 Site L Forearm 10/29/2014 23:10
11 A_IV4 Site L Forearm 10/29/2014 8:31
11 A_IV4 Site R Antecubital 11/10/2014 9:47
11 A_IV4 Site R Antecubital 11/10/2014 1:40
11 A_IV4 Site R Antecubital 11/9/2014 18:18
11 A_IV4 Site R Antecubital 11/9/2014 18:17
11 A_IV4 Site R Antecubital 11/9/2014 11:12
11 A_IV2 Site R Antecubital 10/31/2014 10:26
11 A_IV2 Site R Antecubital 10/30/2014 22:31
11 A_IV2 Site R Antecubital 10/29/2014 23:10
11 A_IV2 Site R Antecubital 10/29/2014 8:31
11 A_IV3 Site R Forearm 11/10/2014 9:47
11 A_IV3 Site R Forearm 11/10/2014 1:40
11 A_IV3 Site R Forearm 11/9/2014 18:18
11 A_IV3 Site R Forearm 11/9/2014 18:17
11 A_IV3 Site R Forearm 11/9/2014 11:12
11 A_IV3 Site R Forearm 11/8/2014 20:57
11 A_IV3 Site R Forearm 11/8/2014 7:40
11 A_IV3 Site R Forearm 11/8/2014 4:24
11 A_IV1 Site R Forearm 10/31/2014 20:57
11 A_IV1 Site R Forearm 10/31/2014 10:26
11 A_IV3 Site R Upper Arm 10/31/2014 20:57
11 A_IV3 Site R Upper Arm 10/31/2014 10:26
11 A_IV3 Site R Upper Arm 10/30/2014 22:31
11 A_IV3 Site R Upper Arm 10/29/2014 23:10
11 A_IV3 Site R Upper Arm 10/29/2014 8:31
11 A_IV3 Site R Upper Arm 10/28/2014 23:52
11 A_IV3 Site R Upper Arm 10/28/2014 13:41
11 A_IV3 Site R Upper Arm 10/28/2014 9:26
我希望我的结果如下：
PatientAccountID FindingAbbr Value CreationTime
----------------------------------------------------------------------
11 A_IV1 Site L Forearm 11/10/2014 9:47
11 A_IV2 Site R Antecubital 10/31/2014 10:26
11 A_IV3 Site R Forearm 11/10/2014 9:47
11 A_IV4 Site R Antecubital 11/10/2014 9:47
大家好： 谢谢大家的帮助。我尝试了你们的所有输入，它确实消除了大部分重复的行。但是现在我为每个FindingAbbr获得了2行，我理解它是因为与它相关的唯一值，但是我有什么方法可以根据最新的CreationTime为每个FindingAbbr只获得一行。以下是我现在得到的结果。 谢谢。
PatientAccountID FindingAbbr Value CreationTime
11 A_IV1 Site L Forearm 11/10/2014 9:47
11 A_IV1 Site R Forearm 10/31/2014 20:57
11 A_IV2 Site R Forearm 11/10/2014 9:47
11 A_IV2 Site R Antecubital 10/31/2014 20:57
11 A_IV3 Site R Forearm 11/10/2014 9:47
11 A_IV3 Site R Upper Arm 10/31/2014 20:57
11 A_IV4 Site R Antecubital 11/10/2014 9:47
11 A_IV4 Site L Forearm 10/31/2014 20:57
答案 0 :(得分：2)
使用窗口功能：
SELECT PatientAccountID, FindingAbbr, Value, CreationTime
FROM (SELECT a.PatientAccountID, e.FindingAbbr, e.Value, e.CreationTime,
ROW_NUMBER() OVER (PARTITION BY e.FindingAbbr ORDER BY e.CreationTime) as seqnum,
COUNT(*) OVER (PARTITION BY e.Value) as cnt
FROM PatientVisit a with (nolock) INNER JOIN
Assessment d with (nolock)
ON a.PatientVisit_oid = d.PatientVisit_oid INNER JOIN
Observation e with (nolock)
ON e.AssessmentID = d.AssessmentID
WHERE a.PatientAccountID = '11' AND
a.VisitTypeCode='IP' AND
a.VisitEndDateTime is null AND
e.Value <> '' AND
e.FindingAbbr IN ('A_IV1 Site', 'A_IV2 Site', 'A_IV3 Site', 'A_IV4 Site')
) t
WHERE seqnum = 1 or seqnum = cnt;
答案 1 :(得分：0)
尝试在FindingAbbr，Value和PatientID上执行GROUP BY，然后在CreationTime上放置MAX()，以便它知道选择最新条目
SELECT a.PatientAccountID ,e.FindingAbbr,
e.Value, max(e.CreationTime) as CreationTime
FROM dbo.vw_ORE_PatientVisitInfo a with (nolock)
JOIN dbo.hAssessment d with (nolock) ON a.PatientVisit_oid = d.PatientVisit_oid
JOIN dbo.HObservation e with (nolock) ON e.AssessmentID = d.AssessmentID
WHERE a.PatientAccountID= '11'
AND a.VisitTypeCode='IP'
AND a.VisitEndDateTime is null
AND e.Value <> ''
AND e.FindingAbbr IN ('A_IV1 Site', 'A_IV2 Site', 'A_IV3 Site', 'A_IV4 Site')
AND EXISTS
(SELECT DISTINCT Max(e.CreationTime)
FROM dbo.HObservation e with (nolock))
Order by a.PatientAccountID)
GROUP BY e.FindingAbbr, e.PatientAccountID, e.Value
答案 2 :(得分：0)
一般的想法是做这样的事情。你可以弄清楚细节。
select yourfields
from table1
join (
select somefield, max(DateTimeField) maxdt
from table1
group by somefield
where whatever) temp on table1.somefield = temp.somefield
and DateTimeField = maxdt
where whatever
答案 3 :(得分：0)
我认为他想要这个：
SELECT e.PatientAccountID ,e.FindingAbbr,
e.Value, max(e.CreationTime) as CreationTime
FROM dbo.vw_ORE_PatientVisitInfo a with (nolock)
JOIN dbo.hAssessment d with (nolock) ON a.PatientVisit_oid = d.PatientVisit_oid
JOIN dbo.HObservation e with (nolock) ON e.AssessmentID = d.AssessmentID
WHERE a.PatientAccountID= '11'
AND a.VisitTypeCode='IP'
AND a.VisitEndDateTime is null
AND e.Value != ''
AND e.FindingAbbr IN ('A_IV1 Site', 'A_IV2 Site', 'A_IV3 Site', 'A_IV4 Site')
AND EXISTS
(SELECT DISTINCT Max(e.CreationTime)
FROM dbo.HObservation e with (nolock))
Order by a.PatientAccountID)
GROUP BY e.FindingAbbr, e.PatientAccountID, e.Value
答案 4 :(得分：0)
像这样的东西
select PatientAccountID,FindingAbbr,Value,LatestCreationTime from
(SELECT
a.PatientAccountID
,e.FindingAbbr
,e.Value
,max(e.CreationTime) as LatestCreationTime
FROM PatientVisit a with (nolock)
INNER JOIN Assessment d with (nolock)
ON a.PatientVisit_oid = d.PatientVisit_oid
INNER JOIN Observation e with (nolock)
ON e.AssessmentID = d.AssessmentID
WHERE
a.PatientAccountID= '11'
AND a.VisitTypeCode='IP'
AND a.VisitEndDateTime is null
AND e.Value != ''
AND e.FindingAbbr IN ('A_IV1 Site', 'A_IV2 Site', 'A_IV3 Site', 'A_IV4 Site')
Group BY a.PatientAccountID
,e.FindingAbbr) as query
Order by a.PatientAccountID