我有以下代码可以复制/克隆所有表,但它不会复制表中的数据。如何调整代码以将数据库与数据一起复制?
<?php
/********************* START CONFIGURATION *********************/
$DB_SRC_HOST='localhost';
$DB_SRC_USER='root';
$DB_SRC_PASS='password';
$DB_SRC_NAME='database1';
$DB_DST_HOST='localhost';
$DB_DST_USER='root';
$DB_DST_PASS='password';
$DB_DST_NAME='database2';
/*********************** GRAB OLD SCHEMA ***********************/
$db1 = mysql_connect($DB_SRC_HOST,$DB_SRC_USER,$DB_SRC_PASS) or die(mysql_error());
mysql_select_db($DB_SRC_NAME, $db1) or die(mysql_error());
$result = mysql_query("SHOW TABLES;",$db1) or die(mysql_error());
$buf="set foreign_key_checks = 0;\n";
$constraints='';
while($row = mysql_fetch_array($result))
{
$result2 = mysql_query("SHOW CREATE TABLE ".$row[0].";",$db1) or die(mysql_error());
$res = mysql_fetch_array($result2);
if(preg_match("/[ ]*CONSTRAINT[ ]+.*\n/",$res[1],$matches))
{
$res[1] = preg_replace("/,\n[ ]*CONSTRAINT[ ]+.*\n/","\n",$res[1]);
$constraints.="ALTER TABLE ".$row[0]." ADD ".trim($matches[0]).";\n";
}
$buf.=$res[1].";\n";
}
$buf.=$constraints;
$buf.="set foreign_key_checks = 1";
/**************** CREATE NEW DB WITH OLD SCHEMA ****************/
$db2 = mysql_connect($DB_DST_HOST,$DB_DST_USER,$DB_DST_PASS) or die(mysql_error());
$sql = 'CREATE DATABASE '.$DB_DST_NAME;
if(!mysql_query($sql, $db2)) die(mysql_error());
mysql_select_db($DB_DST_NAME, $db2) or die(mysql_error());
$queries = explode(';',$buf);
foreach($queries as $query)
if(!mysql_query($query, $db2)) die(mysql_error());
?>