Question

我试图计算任何一个月内新线索的数量和封闭线索的数量。下面的查询正确地返回月份数组，但是如果在月份中有任何潜在客户或关闭，则只计算1，而不是在该月份发生的实际数字。我有什么想法吗？

查询：

$productSql = "SELECT months.monthnum as monthnum, COUNT(contacts.lead_date) as lead_date_month, COUNT(contacts.close_date) as close_date_month, contacts.rep as rep 
                FROM months 
                LEFT JOIN contacts 
                ON months.monthnum = MONTH(contacts.lead_date) 
                    AND months.monthnum = MONTH(contacts.close_date) 
                    AND contacts.compid='$compid' 
                    AND YEAR(contacts.lead_date) = '$year' 
                    AND YEAR(contacts.close_date) = '$year' 
                    AND contacts.rep = '$rep' 
                GROUP BY months.monthnum 
                ORDER BY months.monthnum ASC";

$productResult = mysql_query($productSql, $link) or die(mysql_error());


$label[] = $productRow['monthnum'];
$lead[] = $productRow['lead_date_month'];
$close[] = $productRow['close_date_month'];
};

echo "[".json_encode($label).",".json_encode($lead).",".json_encode($close)."]";

结果：

[["January","February","March","April","May","June","July","August","September","October","November","December"],
["0","0","0","0","0","0","0","0","1","1","0","0"],
["0","0","0","0","0","0","0","0","1","1","0","0"]]

**请不要因为使用mysql而惩罚我。这个项目完成后我立即抛弃它。

Answer 1

您构建JOIN条件的方式只会从MONTH(contacts.lead_date) = MONTH(contacts.close_date)的记录中获得结果。

要解决这个问题并获得实际的Count，我建议将该语句拆分为两个查询：

SELECT 
    a.monthnum, 
    a.lead_date_month, b.close_date_month, 
    b.close_date_month / a.lead_date_month
FROM
(
-- Count number of new leads
SELECT 
    months.monthnum as monthnum, 
    COUNT(*) as lead_date_month, 
    contacts.rep as rep 
FROM 
    months 
    LEFT JOIN contacts
ON 
    months.monthnum = MONTH(contacts.lead_date) 
    AND contacts.compid='$compid' 
    AND YEAR(contacts.lead_date) = '$year' 
    AND contacts.rep = '$rep' 
GROUP BY 
    months.monthnum 
ORDER BY 
    months.monthnum ASC
) as a
JOIN
(
-- Count number of closed leads
    SELECT 
    months.monthnum as monthnum, 
    COUNT(*) as close_date_month, 
    contacts.rep as rep 
FROM 
    months 
    LEFT JOIN contacts
ON 
    months.monthnum = MONTH(contacts.close_date) 
    AND contacts.compid='$compid' 
    AND YEAR(contacts.close_date) = '$year' 
    AND contacts.rep = '$rep' 
GROUP BY 
    months.monthnum 
ORDER BY 
    months.monthnum ASC
) as b
ON a.monthnum = b.monthnum

MySQL并没有那么糟糕。但MariaDB更好，你是对的： - ）

在左连接表mysql中SELECT COUNT（）

1 个答案: