在php中组合或交叉两个不同长度的数组

Question

第一个数组是$niz：

Array (
  [Swansea] => 4
  [Stoke City] => 3
  [Sunderland] => 3
  [Southampton] => 5
  [Liverpool] => 3
  [Manchester United] => 2
  [Hull City] => 1
  [Tottenham] => 2
  [Newcastle Utd] => 1
  [Aston Villa] => 1
  [West Ham] => 2
  [Crystal Palace] => 3
  [Chelsea] => 3
)

第二个数组是$ niz1：

Array (
  [Stoke City] => 2
  [Sunderland] => 2
  [Liverpool] => 1
  [Hull City] => 1
  [Tottenham] => 1
  [Manchester United] => 1
  [Newcastle Utd] => 1
  [Crystal Palace] => 3
  [Chelsea] => 1

）

如何组合这些数组以获取$niz2（键的顺序类似于数组$niz1，值来自匹配的数组$niz），如：

$niz2：

Array (
  [Stoke City] => 3
  [Sunderland] => 3
  [Liverpool] => 3
  [Hull City] => 1
  [Tottenham] => 2
  [Manchester United] => 2
  [Newcastle Utd] => 1
  [Crystal Palace] => 3
  [Chelsea] => 3

）

我尝试使用函数array_merge()，但我得到了空值，并尝试使用array_intersect_key()。

Answer 1

试试这个

foreach ($niz1 as $k=>$n)
{
    if(in_array($k,$niz1))
    {
        $niz2[$k]=$niz[$k];
    }

}
print_r($niz2);

Answer 2

试试这个：

$temp = array_intersect_key($niz, $niz1);

foreach ($niz1 as $k => $v) {
    $niz2[$k] = $temp[$k];
}

Answer 3

//(overwrites the values of $niz1 with those of $niz2)
$bif=array_merge($niz1,$niz);  

//(removes everything from $bif that is not in $niz1)
$result=array_intersect($niz1,$bif);