使用javascript中的splice删除嵌套数组中的项目

时间:2014-11-10 12:53:57

标签: javascript arrays if-statement for-loop splice

我在使用splice从数组中删除项目时遇到问题。首先,我有一个名为player的Array,它包含另外三个名为tier1,tier2和tier3的Arrays。所有这三个数组都存储了值,我希望操作它们。我的页面上有一个输入和一个按钮,单击该按钮可激活与拼接数组相关的JS功能。 我已经设置了一个带有FOR循环的IF语句,以便查看tier1来检查输入文本是否与数组中的值匹配,如果在tier1中找不到文本,那么它应该执行相同的操作tier2然后是tier3,如果输入文本不在任何数组中,则最后显示错误消息。如果输入文本在tier1中,该函数可以正常工作但由于某种原因它似乎没有运行else if语句,我在下面提供了我的代码我不确定这只是一个语法错误还是我是缺少某种功能。非常感谢提前

var player=[]
var tier1=["p1","p2","p3"]
var tier2=["p4","p5","p6","p7"]
var tier3=["p8","p9","p10","p11"]

function removeFunction() {
    if (document.getElementById("removePlayer").value !== "") {
        for (index = 0; index < tier1.length; index++) {
            if(document.getElementById("removePlayer").value == tier1[index]) {
        tier1.splice(index, 1);
            playerFunction();
            playerAlert = "Player Removed";
            document.getElementById("test1").innerHTML = playerAlert;
            document.getElementById("test2").innerHTML = tier1;
    }}
    } else if (tier1[index] !== document.getElementById("removePlayer").value) {
        for (index = 0; index < tier2.length; index++) {
        if(tier2[index] == document.getElementById("removePlayer").value) {
            tier2.splice(index, 1);
            playerFunction();
            playerAlert = "Player Removed";
            document.getElementById("test1").innerHTML = playerAlert;
            document.getElementById("test2").innerHTML = tier2;
        }}
    } else if (tier2[index] !== document.getElementById("removePlayer").value) {
        for (index = 0; index < tier3.length; index++) {
        if(tier3[index] == document.getElementById("removePlayer").value) {
            tier3.splice(index, 1);
            playerFunction();
            playerAlert = "Player Removed";
            document.getElementById("test1").innerHTML = playerAlert;
            document.getElementById("test2").innerHTML = tier3;
        }
    }} else {
        playerAlert = "Nothing happened";
        document.getElementById("test1").innerHTML = playerAlert;
    }
}

http://jsfiddle.net/9r73ntsc/1/

1 个答案:

答案 0 :(得分:0)

这会对你有所帮助

function removeFunction() {
    if (document.getElementById("removePlayer").value !== "") {
        for (index = 0; index < tier1.length; index++) {
            if (document.getElementById("removePlayer").value == tier1[index]) {
                tier1.splice(index, 1);
                playerFunction();
                playerAlert = "Player Removed";
                document.getElementById("test1").innerHTML = playerAlert;
                document.getElementById("test2").innerHTML = tier1;
                return;
            }
            if (document.getElementById("removePlayer").value == tier2[index]) {
                tier2.splice(index, 1);
                playerFunction();
                playerAlert = "Player Removed";
                document.getElementById("test1").innerHTML = playerAlert;
                document.getElementById("test2").innerHTML = tier2;
                return;
            }
            if (document.getElementById("removePlayer").value == tier3[index]) {
                tier3.splice(index, 1);
                playerFunction();
                playerAlert = "Player Removed";
                document.getElementById("test1").innerHTML = playerAlert;
                document.getElementById("test2").innerHTML = tier3;
                return;
            }
        }
    }
    playerAlert = "Nothing happened";
    document.getElementById("test1").innerHTML = playerAlert;
}

编辑:更正了从tier2 [index]到tier3 [index]

的最终IF语句