Question

我正在创建一个功能，通过删除重复项来缩短列表。我一直在摆弄代码一段时间，每当我摆脱一个错误时，我就会得到另一个错误。有什么想法吗？

def delete_adjacent():
    user_list = []
    list_length = int(input("How long do you want your list? "))
    check = 0
    characters = ""
    while len(user_list) != list_length:
        new_item = input("Input your item for the list: ")
        user_list.append(new_item)
    print (user_list)
    while check != list_length:
        item = user_list[check]
        count = user_list.count(item)
        if count == 1:
            check += 1
        while count > 1:
            user_list.remove(item)
    return
delete_adjacent()

Answer 1

只需使用set

即可

set是一个像list一样的对象，没有重复项。

user_list = list(set(user_list))

您可以将list转换为set以删除重复内容，然后将其转换回list以免影响代码流

Answer 2

感谢“无花果”，我找到了最简单的方法。

def delete_adjacent():
    user_list = []
    list_length = int(input("How long do you want your list? "))
    characters = ""
    while len(user_list) != list_length:
        new_item = input("Input your item for the list: ")
        user_list.append(new_item)
    print(set(user_list))
    return
delete_adjacent()

Answer 3

我想你想这样：

>>> def remove_dup():
...     user_list = []
...     list_length = int(input("how long do you want your list? :"))
...     while len(user_list) < list_length:
...         item = input("enter a item: ")
...         if item != "" and item not in user_list:
...             user_list.append(item)
...         else: print "Either item was null or was already present in list"
...     return user_list
... 
>>> remove_dup()
how long do you want your list? :4
enter a item: 1
enter a item: 3
enter a item: 1
Either item was null or was already present in list
enter a item: 4
enter a item: 6
[1, 3, 4, 6]

通过删除重复来缩短列表

3 个答案: