Question

我正在努力完成一项任务。我正在尝试创建一个仅显示Journal元素的函数，其中Author1 / Auth1是作者之一。我确实列出了三个Journal元素，但我只能将每个Journal分成一个新行。 我无法将结果中的每个Journal-child（最好是文本nexto值）与新行(<br />)分开。

我有以下XML文档：

<Journals>
    <Journal>
        <Title>Title1</Title>
        <AuthorName>Author1</AuthorName> 
        <AuthorName>Author2</AuthorName> 
        <AuthorName>Author3</AuthorName>
        <JournalName>One</JournalName>
    </Journal>
    <Journal>
        <Title>Title2</Title>
        <AuthorName>Author2</AuthorName>
        <AuthorName>Author1</AuthorName>
        <JournalName>Two</JournalName>
    </Journal>
    <Journal>
        <Title>Title3</Title>
        <AuthorName>Author3</AuthorName>
        <JournalName>Three</JournalName>
    </Journal>
    <Journal>
        <Title>Title4</Title>
        <AuthorName>Author3</AuthorName> 
        <AuthorName>Author2</AuthorName> 
        <AuthorName>Author4</AuthorName>
        <JournalName>Four</JournalName>
    </Journal>
    <Journal>
        <Title>Title5</Title>
        <AuthorName>Author2</AuthorName> 
        <AuthorName>Auth1</AuthorName>
        <JournalName>Five</JournalName>
    </Journal>
    <Journal>
        <Title>Title6</Title>
        <AuthorName>Author2</AuthorName> 
        <AuthorName>Author3</AuthorName>
        <JournalName>Six</JournalName>
    </Journal>
</Journals>

以下PHP文档：

<?php
  header('Content-Type: text/html; charset=utf-8');
  error_reporting(E_ERROR | E_WARNING | E_PARSE);


/* FUNCTION FOR ALL ARTICLES PUBLISHED BY Author1 */
  function taskOne()              
    {   
    $doc = new DOMDocument();
    $doc->load("file.xml"); 
    $xml = new DOMXPath($doc);

    $query = $xml->evaluate("/Journals/Journal/AuthorName[contains(. , 'Author1') or contains(. , 'Auth1')]/..");
    foreach ($query as $temp)
      {
      echo $temp->nodeValue . "<br />";
      }
    }
    taskOne();
?>

现在的另一个问题：如何使用XPath查询：/Journals/Journal[contains(AuthorName, 'Author1') or contains(AuthorName, 'Auth1')]仅列出作者是最佳作者的日记，而不是那些他的孩子兄弟二号或三号的日记？ 以下是XPath查询的最终输出： /Journals/Journal/AuthorName[contains(. , 'Author1') or contains(. , 'Auth1')]/..

Title1 Author1 Author2 Author3 One 
Title2 Author2 Author1 Two 
Title5 Author2 Auth1 Five

以下是XPath查询的最终输出： /Journals/Journal[contains(AuthorName, 'Author1') or contains(AuthorName, 'Auth1')]

Title1 Author1 Author2 Author3 One

对于澄清，这是我想要实现的目标：

Title: Title1 
Journal author: Author1 
Journal author: Author2 
Journal author: Author3 
Journal name:   One

Title: Title2
Journal author: Author2 
Journal author: Author1 
Journal name:   Two 

Title: Title5 
Journal author: Author2 
Journal author: Auth1 
Journal name:   Five

Answer 1

您可以定位具有包含您想要的针的子<Journal>的{{1}}。你已经离开了：

<AuthorName>

Sample Output

PHP，XML＆amp; XPath：显示特定节点

1 个答案: