Question

我现在正在Eclipse中开发一系列问题后，我正在尝试使用以下语法解析JSONObject：

{"d":
  [
  {"PartitionKey":"fec35985-5e82-47b4-94da-4aed9da9bf72",
  "RowKey":"b8a57f4a-e057-4b43-9f49-99fa7d19d6a0",
  "codigo_dane":"115183000392",
  "nombre_de_la_institucion":"I.E. JOSE MARIA POTIER",
  "nombre_sede_educativa":"PRINCIPAL",
  "rector":"MIGUEL ALBERTO MEDINA RUIZ",
  "direccion":"KRA. 7 No. 4-58",
  "telefono":"7892195",
  "correo_electronico":"chita_josemariapotier@desboyaca.gov.co",
  "no_de_estudiantes":"250"},
  {"PartitionKey": ...
  }
  ]
}

使用此方法来请求JSONObject：

public static JSONObject requestWebService（String serviceUrl）{ disableConnectionReuseIfNecessary（）;

    HttpURLConnection urlConnection = null;
    try {
        // create connection
        URL urlToRequest = new URL(serviceUrl);
        urlConnection = (HttpURLConnection)
                urlToRequest.openConnection();
        urlConnection.setConnectTimeout(CONNECTION_TIMEOUT);
        urlConnection.setReadTimeout(DATARETRIEVAL_TIMEOUT);

        // handle issues
        int statusCode = urlConnection.getResponseCode();
        if (statusCode == HttpURLConnection.HTTP_UNAUTHORIZED) {
            // handle unauthorized (if service requires user login)
        } else if (statusCode != HttpURLConnection.HTTP_OK) {
            // handle any other errors, like 404, 500,..
        }

        // create JSON object from content
        InputStream in = new BufferedInputStream(
                urlConnection.getInputStream());
        return new JSONObject(getResponseText(in));

    } catch (MalformedURLException e) {
        // and a lot of other exceptions; I don't include them to keep this short
    } finally {
        if (urlConnection != null) {
            urlConnection.disconnect();
        }
    }

    return null;
}

当我尝试使用此方法接收JSONObject（它似乎直到现在才有效;我过去常常得到一些JSONExceptions但我现在没问题）：

public List<String> getAllItemsNames(JSONObject JObject) {  
    List<String> names = new ArrayList<String>();
    try {
        JSONArray objs = JObject.getJSONArray("d");
        for(int i = 0; i < objs.length(); i++) {
            JSONObject obj = objs.getJSONObject(i);
            names.add(obj.getString(KEY_NAME));
        }
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        names.add("No values available!");
        e.printStackTrace();
    }
    return names;
}

我收到错误：“d没有值”。我认为这可能是因为数组的名称而发生的，因为我不确定它是否真的是“d”。我尝试了一个空格（“”），但我仍然得到例外。请帮忙！

从Web服务解析JSONObject（d没有值）

0 个答案: