我必须开发两个功能。一个是应用程序级别函数，它合并使用动态数组实现的两个排序列表。另一个是相同的，除了它应该是一个成员函数。我得到无效的分配大小。当我跟踪函数时，它成功返回而没有错误购买，一旦我到达原始调用代码，我得到错误。这是两个函数的代码。
应用程序级别功能：
ArraySortedType& merge(const ArraySortedType& list1, const ArraySortedType& list2)
{
ItemType temp;
ArraySortedType ret, list1Copy=list1, list2Copy=list2;
list1Copy.ResetList();
while (list1Copy.GetNextItem(temp) == Success)
ret.InsertItem(temp);
list2Copy.ResetList();
while (list2Copy.GetNextItem(temp) == Success)
ret.InsertItem(temp);
return ret;
}
会员功能：
ArraySortedType& ArraySortedType::merge(const ArraySortedType& list)
{
ArraySortedType s, copy = list;
ItemType temp;
copy.ResetList();
while (copy.GetNextItem(temp) == Success)
s.InsertItem(temp);
for (int k = 0; k < length; k++)
s.InsertItem(info[k]);
return s;
}
我称之为函数的代码：
ArraySortedType u = merge(s, n);
//ArraySortedType k = merge(s, n);
cout << "Length of u is: " << u.LengthIs() << endl;
// cout << "Length of k is: " << k.LengthIs() << endl;
即使是注释掉的代码也无法正常工作。
还有很多代码用于实现我遗漏的ArraySortedType，因为我认为这是不必要的。其中大部分已经在实验室中提供。 InsertItem是由我实现的，并且使用了很多，所以我将它包含在这里：
Error_Code ArraySortedType::InsertItem ( ItemType item)
{
if(!length)
{
info[0] = item;
length++;
return Success;
}
for(int i=0;i<=length;i++)
{
if(info[i].ComparedTo(item) != LESS || i==length)
{
for(int j=length;j>i;j--)
info[j] = info[j-1];
info[i]=item;
length++;
return Success;
}
}
return Fail;
}
已经给出了GetNextItem（）和ResetList（），所以他们不能解决问题，所以我会把它们留下来但只是告诉我它们是否是必需的。
我已经跟踪了他们两个并搜索了相当多的但这个问题让我挠头。任何帮助将不胜感激。
编辑：
我想有必要实现ArraySortedList。这里是。猜猜我真的不希望任何人真正经历过它：
//ArraySortedType.cpp
#include "ArraySortedType.h"
ArraySortedType::ArraySortedType (int max_items)
{
length =0;
MAX_ITEMS = max_items;
currentPos =-1;
try
{
info = new ItemType[MAX_ITEMS];
}
catch(std::bad_alloc exception)
{
//Severe problem, do not keep program running
cout <<"Memory full "<< endl;
exit(1);
}
}
ArraySortedType::~ArraySortedType()
{
delete [] info;
info = NULL;
}
void ArraySortedType::ResetList ( )
{
currentPos = -1;
}
bool ArraySortedType::IsFull ( ) const
{
if(length == MAX_ITEMS)
{
try
{//Check if memory allocation is fine
ItemType * temp = new ItemType[2*MAX_ITEMS];
delete [] temp;
return false;
}
catch(std::bad_alloc exception)
{
return true;
}
}
return false;
}
bool ArraySortedType::IsEmpty () const {
return (length==0);
}
int ArraySortedType:: LengthIs () const {
return length;
}
Error_Code ArraySortedType::DeleteItem ( ItemType item ) {
int location = 0;
while ((item.ComparedTo(info[location]) != EQUAL ) && location < length)
location++;
if (location == length) return Fail;
info[location] = info[length - 1];
length--;
return Success;
}
Error_Code ArraySortedType::GetNextItem (ItemType& item) {
currentPos++;
if( currentPos == length ) return Fail;
item = info[currentPos] ;
return Success;
}
ArraySortedType::ArraySortedType(const ArraySortedType & ust)
{
MAX_ITEMS =ust.MAX_ITEMS;
length=ust.length;
try
{
info = new ItemType[MAX_ITEMS];
}
catch(std::bad_alloc exception)
{
//Severe problem, do not keep program running
cout <<"Memory full "<< endl;
exit(1);
}
for(int i=0;i<length; i++)
info[i] = ust.info[i];
currentPos=ust.currentPos;
}
ArraySortedType& ArraySortedType::operator=(const ArraySortedType & ust)
{
if(this == &ust) return *this;
if(MAX_ITEMS !=ust.MAX_ITEMS)
{
delete [] info;
MAX_ITEMS = ust.MAX_ITEMS;
try
{
info = new ItemType[MAX_ITEMS];
}
catch(std::bad_alloc exception)
{
//Severe problem, do not keep program running
cout <<"Memory full "<< endl;
exit(1);
}
}
currentPos=ust.currentPos;
length=ust.length;
for(int i=0;i<length; i++)
info[i] = ust.info[i];
return *this;
}
//Assumes that an employee has unique ID
bool ArraySortedType::operator==(const ArraySortedType & ust)
{
if(this == &ust) return true;
if(length!=ust.length) return false;
if(currentPos!=ust.currentPos) return false;
for(int i=0;i<length; i++)
if(info[i].ComparedTo(ust.info[i])!=EQUAL) return false;
return true;
}
Error_Code ArraySortedType::InsertItem ( ItemType item)
{
if(!length)
{
info[0] = item;
length++;
return Success;
}
for(int i=0;i<=length;i++)
{
if(info[i].ComparedTo(item) != LESS || i==length)
{
for(int j=length;j>i;j--)
info[j] = info[j-1];
info[i]=item;
length++;
return Success;
}
}
return Fail;
}
Error_Code ArraySortedType::RetrieveItem (ItemType& item , bool& found)
{
found = false;
int front = 0, back = length - 1, midpoint=(length-1)/2;
while (front<=back)
{
switch (info[midpoint].ComparedTo(item))
{
case EQUAL:
item = info[midpoint];
found = true;
break;
case LESS:
front = midpoint + 1;
break;
case GREATER:
back = midpoint - 1;
break;
}
if (found)
break;
midpoint = ((back - front) / 2 + front);
}
return Fail;
}
Error_Code ArraySortedType::Delete(ItemType startKey, ItemType endKey)
{
bool startFound = false, endFound = false;
int numberDeleted=0, startLocation;
bool deleting = false;
for (int i = 0; i < length; i++)
{
if (info[i].ComparedTo(startKey) == EQUAL)
{
startLocation = i;
deleting = true;
startFound = true;
}
if (deleting)
numberDeleted++;
if (info[i].ComparedTo(endKey) == EQUAL)
{
deleting = false;
endFound = true;
}
}
if (!(startFound || endFound))
return Fail;
length -= numberDeleted;
for (int i = startLocation; i < length; i++)
info[i] = info[i + startLocation];
return Success;
}
ArraySortedType ArraySortedType::RetrieveItemsInRange(ItemType startKey, ItemType endKey)
{
ArraySortedType r;
bool startFound = false, endFound = false;
int numberDeleted = 0, startLocation;
bool retrieving = false;
for (int i = 0; i < length; i++)
{
if (info[i].ComparedTo(startKey) == EQUAL)
{
startLocation = i;
retrieving = true;
startFound = true;
}
if (retrieving)
r.InsertItem(info[i]);
if (info[i].ComparedTo(endKey) == EQUAL)
{
retrieving = false;
endFound = true;
}
}
return r;
}
ArraySortedType& ArraySortedType::merge(const ArraySortedType& list)
{
ArraySortedType s, copy = list;
ItemType temp;
copy.ResetList();
while (copy.GetNextItem(temp) == Success)
s.InsertItem(temp);
for (int k = 0; k < length; k++)
s.InsertItem(info[k]);
return s;
}
ItemType被定义为类Employee。我真的希望我也不必将它包含在这里。 Employee类有一个compareTo类，定义如下：
RelationType Employee::ComparedTo(const Employee & e)
{
if(eid < e.eid) return LESS;
else if(eid == e.eid) return EQUAL;
else return GREATER;
}
有一个称为关系类型的枚举，其值为LESS，EQUAL和GREATER。