Question

我写了一个程序，它读取一个文本文件来显示足球比分，现在文本文件的排列使其包含错误，我正在尝试编写一个程序来计算这些错误。文本文件的排列如下：

Hull City : Sunderland : 2 : 3
Chelsea : Manchester City :1
Fulham : Leeds United : 1 : 2
Wigan : Tottenham : 1 : x
: :2:0

所以上面缺少团队名称，缺少分数，一些分数被X替换。我不能为我的生活弄清楚如何引入计数器来计算错误的数量，任何想法都在一个起点上/解决方案将非常感谢，谢谢！

这是我的完整代码：主：

public class main {

public static void main(String[] args) {

    String userInput;

    readFile readScores = new readFile();

    do 
    {
        userInput = readScores.getUserInput();
        if(userInput.equalsIgnoreCase("S"))
            readScores.printScores();
            readScores.totalGoals();
            readScores.errorCount();

    } while (!userInput.equalsIgnoreCase("E"));
        System.out.println("****************Exiting application****************");
        System.exit(0);


}

}

Readfile类：

public class readFile {


String [] stringArr;

Scanner scan = new Scanner(System.in);

public String getUserInput()
{
    String userInput;

    System.out.println("Select your option:\nS - Show Scores \nE - Exit");

    userInput = scan.nextLine();

    return (userInput);

}

public void printScores()
{

    String sep = ":";
    File inputfile = new File ("P:/SD/Assignment1/results2.txt");

        String line = "";



        try {
            Scanner filescan = new Scanner(inputfile);
            while(filescan.hasNext())
            {
                line = filescan.nextLine();


                stringArr = line.split(sep);
                if(stringArr.length ==  4)
                {                       

                    System.out.println(stringArr[0]+"\t [" +stringArr[2]+"]\t|" + stringArr[1]+"\t["+ stringArr[3]+" ]\n");


                }

                else
                {
                    throw new IllegalArgumentException("String " + line + " does not contain " + sep);
                }



             }
            filescan.close();


        }
            catch (FileNotFoundException e)
            {
                System.out.println("problem " +e.getMessage());
            }

        }
    public void totalGoals()
    {

        int[] num = new int[stringArr.length]; 
        int count = 0;
        for (int i = 0; i<stringArr.length; i++)
        {
            System.out.println(stringArr[i]);
            num[i] = Integer.parseInt(stringArr[i]);
            count = count + num[i];
            System.out.println(count);
        }
    }

    public void errorCount()
    {
        String line;
        int errorCount=0;
        String[] strArr;
        try
        {

            BufferedReader br = new BufferedReader(new FileReader("P:/SD/Assignment1/results2.txt"));
            while(line = br.readLine() != null)
            {
                strArr = line.split(":");
                if(strArr.length==4){
                    if(strArr[1].trim().isEmpty()) errorCount++;
                    if(strArr[2].trim().isEmpty()) errorCount++;
                    if(strArr[3].trim().indexOf("x")>=0) errorCount++;
                    if(strArr[4].trim().indexOf("x")>=0) errorCount++;
                }
            }
        }
        catch(Exception e){
            //error handling
        }
        System.out.println("Error count: "+errorCount);
    }
    }

UPDATE ::

public void errorCount()
        {

        String line;
        int errorCount=0;
        String[] strArr;
        String[] parts = line.split(":"); <--- ERROR IS HERE
        if (parts.length != 4) {
            errorCount++;

        }
        for (String part : parts) {
            if (part.trim().isEmpty()) {
                errorCount++;
                break; 
            }
        }
        if (!(isNumeric(parts[2].trim()) && isNumeric(parts[3].trim()))) { //counts one error, otherwise, check each one of them and if both are not numeric, count this as two errors
            errorCount++;
            // continue with the following line
        }
    }

Answer 1

我会建议这样的事情：

String line;
int errorCount=0;
String[] strArr;
try{
    BufferedReader br = new BufferedReader(new FileReader(yourTextFile));
    while((line = br.readLine()) != null){
        strArr = line.split(":");
        if(strArr.length==4){
            if(strArr[0].trim().isEmpty()) errorCount++;
            if(strArr[1].trim().isEmpty()) errorCount++;
            if(strArr[2].trim().indexOf("x")>=0) errorCount++;
            if(strArr[3].trim().indexOf("x")>=0) errorCount++;
        }
        else errorCount++;
    }
}
catch(Exception e){
    //error handling
}
System.out.println("Error count: "+errorCount);

Answer 2

您可以根据正则表达式检查线条。每个不匹配的行都包含错误。

正则表达式的起点：

/(.+) : (.+) : (\d+) : (\d+)/

括号允许您获取球队名称和分数。

Answer 3

int errorCounter = 0; //initialize the errorCounter to zero
try{
    BufferedReader br = new BufferedReader(new FileReader(yourTextFile));
    while((line = br.readLine()) != null){ //read the file line by line

      //Check that each line is split into 4 parts (delimited by ':')
      String[] parts = line.split(":");
      if (parts.length != 4) {
         errorCounter++;
         continue; //continue with the following line
      }

     // Then, check if some of the parts are null, like that:

     for (String part : parts) {
        if (part.trim().isEmpty()) {
            errorCounter++;                
        }
     }    

    //Finally, you can check if the last two parts contain numbers, using [this `isNumeric()` method][2], like that:

    if (!(isNumeric(parts[2].trim())) { //checks if the third part is a number
        errorCounter++;
    }

    if (!(isNumeric(parts[3].trim())) { //checks if the last part is numeric
        errorCounter++;
    }
} catch(IOException ex) {
     System.err.println(ex);
}

可以找到isNumeric（）方法here。

请注意，此解决方案会在同一行上计算多个错误。如果你想计算每行一个错误，你可以简单地使用Lorenz Meyer建议的单线程。

计算文本文件中的错误数

3 个答案: