Question

我正在研究一个基本的控制台程序，如下所示。我很生气，后一段代码不起作用。检查用户输入年龄并从Console.WriteLine重新运行代码的最佳方法是什么（“好的。现在请输入您的年龄。”）;到if语句。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Practice
{
    class Program
    {
        static void Main(string[] args)
        {
           Console.WriteLine("Thank you for participating in this survey. Please take a moment to fill out the required information.");
           Console.WriteLine("Please Type Your Name");

            string name = Console.ReadLine();

            Console.WriteLine("Okay. Now please enter your age.");

            string age = Console.ReadLine();

            Console.WriteLine("Your information has been submitted.");

            Console.WriteLine("Name: " + name + "\n" + "Age: " + age);

            Console.ReadLine();

            int newAge = Int32.Parse(age);

            if (newAge => 18) 
            {

            }

        }
    }
}

Answer 1

替换它：

 int newAge = Int32.Parse(age);

用这个

 int newAge = Convert.ToInt32(age);

。如果你想更好地编码，请使用try-catch

try
{
int newAge = Convert.ToInt32(age);
}
catch(FormatException)
{
//do something
}

Answer 2

您还可以使用TryParse，它为您执行错误测试，并将解析后的值作为out参数返回。当TryParse返回bool值时，您可以轻松检查转换是否有效。

string age = null;
int ageValue = 0;
bool succeeded = false;

while (!succeeded)
{
    Console.WriteLine("Okay, now input your age:");
    age = Console.ReadLine();
    succeeded = int.TryParse(age, out ageValue);
}

你还可以将它反转为......而

string age = null;
int ageValue = 0;
do
{
    Console.WriteLine("Okay, now input your age:");
    age = Console.ReadLine();
} while (!int.TryParse(age, out ageValue));

基于条件重新运行代码块

2 个答案: