如果在while循环中无法实现

Question

请帮助我。我无法在WHILE中实现IF：

    while IFS=';' read one two three; 
do

if (( $three >= 1 )) #this is a line that i can't understand

then X=$(for i in $two
   do BIN=$(echo "obase=10; ibase=16; $i" | bc )
   echo $BIN
   done)
fi
done < /testcsv.csv

，输出为：

./test.sh: line 34: ((: <= 1 : syntax error: operand expected (error token is "<= 1 ")

Answer 1

bash中IF的语法如下：

if [ conditional expression ]

在你的情况下：

if [ $three >= 1 ]