Question

我需要的是对我的代码进行一些修改，以便我的空心钻石的每一部分都印有一个字母＆＃34; HURRICANE＆＃34;

我的代码是：

    String st1="HURRICANE";
    int a = 0;
   for(int i = 5;i >= 1;i--){
       for(int j = 1;j <= 9;j++){
        if(j == i || (10 - i) == j)
            {
            System.out.print(st1.charAt(a));  \\needs change
        }
        else {
            System.out.print(' ');
        }
        }
     System.out.println();
    }
    for(int i =2;i <= 5;i++){
       for(int j = 1;j <= 9;j++){
        if(j == i || (10 - i) == j){
            System.out.print(st1.charAt(a));   \\needs change
        }
        else
             {
            System.out.print(' ');
        }
        }
     System.out.println();
    }

输出结果如下：

我需要修改我的＆＃34; charAt＆＃34;声明一点，所以它出来了：

我该如何制作我的印刷声明？

Answer 1

值得注意的是，提供的示例仅适用于与“HURRICANE”相同长度的字符串。优秀的解决方案适用于所有字符串。

部分解决方案供您完成，因为我认为这是您的课程，我不希望您复制/粘贴/失败考试：P

  public static void main(String[] args) {
    String st1 = "HURRICANE";
    char[] st1CharArray = st1.toCharArray();
    int maxSpaces = st1CharArray.length / 2 + 1;
    for (int i = 0; i <= st1CharArray.length / 2; i++) {
      if (i == 0) {
        System.out.println(getSpacesString(maxSpaces) + st1CharArray[i]);
      } else {
        System.out.println(getSpacesString(maxSpaces - i) + st1CharArray[i] + getSpacesString(i * 2 - 1)
            + st1CharArray[i]);
      }
    }
    // Loop from st1CharArray.length / 2 + 1 and get the second half done.

  }

  private static String getSpacesString(int numberOfSpaces) {
    StringBuilder strBuilder = new StringBuilder();
    for (int i = 0; i < numberOfSpaces; i++) {
      strBuilder.append(" ");
    }
    return strBuilder.toString();
  }

Answer 2

 String st1="HURRICANE";
   int a = 0;
   for(int i = 5;i >= 1;i--){
       for(int j = 1;j <= 9;j++){
        if(j == i || (10 - i) == j)
            {
            System.out.print(st1.charAt(5-i));
        }
        else {
            System.out.print(' ');
        }
        }
     System.out.println();
    }
    for(int i =2;i <= 5;i++){
       for(int j = 1;j <= 9;j++){
        if(j == i || (10 - i) == j){
            System.out.print(st1.charAt(3+i));
        }
        else
             {
            System.out.print(' ');
        }
        }
     System.out.println();
    }

Answer 3

//: Playground - noun: a place where people can play

import UIKit

var name : String = "HURRICANE"
var dimensions : Int = name.count - 1
var k : Int = 0

for rows in 0...dimensions{
    for columns in 0...dimensions{
        k = abs( (dimensions/2) - rows )

        if columns == k || columns == dimensions - k{
            print(Array(name)[rows], terminator: "")
        }
        else{
            print(" ", terminator: "" )
        }
    }

    print("")
}

Answer 4

假设一个单词有奇数个字符，否则我们会得到一个弯曲的菱形。

Try it online!

public static void main(String[] args) {
    String str = "abrahadabra";
    int n = str.length() / 2;
    for (int i = -n, ch = 0; i <= n && ch < str.length(); i++, ch++) {
        for (int j = -n; j <= n; j++)
            if (Math.abs(i) + Math.abs(j) == n)
                System.out.print(str.charAt(ch));
            else
                System.out.print(" ");
        System.out.println();
    }
}

输出：

     a     
    b b    
   r   r   
  a     a  
 h       h 
a         a
 d       d 
  a     a  
   b   b   
    r r    
     a

我需要帮助制作一个空心的钻石

4 个答案: